The molar mass of methylammonium bromide is 111u.
<h3>What is molar mass?</h3>
The molar mass is defined as the mass per unit amount of substance of a given chemical entity.
Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.
Add it all together and put units of grams/mole after the number.
Atomic weight of H is 1u
Atomic weight of N is 14u
Atomic weight of C is 12u
Atomic weight of Br is 79u
Calculating molar mass of
=2(1 x3+ 14+12+ 1 x 3 +79) = 111u
Hence, the molar mass of methylammonium bromide is 111u.
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CH4 is the molecular formula for methane.
Answer:
Atomic models are important because, they help us visualize the interior of atoms and molecules, and thereby predicting properties of matter.
Explanation:
We study the various atomic models in our course of study because, it is important for us to know, how did people come to the present concept of an atom. How did physics evolve from classical to quantum physics.
All these are important for us to know and thus, knowledge about various atomic models, their discoveries and drawbacks and finally improvements based on scientific evidence present at that time is important for us to understand the underlying theory very well.
Answer:
V2 gas = 2.33 L
Explanation:
assuming ideal gas:
∴ n gas = 1 mol
∴ P1 standard = 1 atm
∴ V1 gas = 3.5 L
∴ P2 = 1.5 atm ⇒ V2 = ?
state 1:
∴ P1V1 = nRT1
⇒ P1V1/T1 = nR
state 2:
⇒ P2V2/T2 = nR
(1) = (2)
⇒ P1V1/T1 = P2V2/T2
assiming: T1 = T2
⇒ P1V1 = P2V2
⇒ V2 = P1V1/P2
⇒ V2 = ((1 atm)(3.5 L))/(1.5 atm)
⇒ V2 = 2.33 L
Answer:
B) weathering and erosion
Explanation:
The two processes responsible for changing metamorphic and igneous rocks into sedimentary rocks is weathering and erosion.
Weathering is the defined as the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Erosion is the removal of weathered materials from the surface of the earth.
The process of erosion and weathering serves to convert igneous and metamorphic rocks into sediments by which a sedimentary rock is formed.