Answer:
The value of the heat capacity of the Calorimeter
= 54.4 
Explanation:
Given data
Heat added Q = 4.168 KJ = 4168 J
Mass of water
= 75.40 gm
Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c
From the given condition
Q =
ΔT +
ΔT
Put all the values in above equation we get
4168 = 75.70 × 4.18 × 11.24 +
× 11.24
611.37 =
× 11.24
= 54.4 
This is the value of the heat capacity of the Calorimeter.
Answer:
"The five factors are: the latitude zone, the elevation of the land, topography (landforms), ocean currents and winds."
Explanation:
1 carot = 0.2 grams
1.5 carot = 0.3 grams.
1 mol of Carbon = 12 grams
x mol = 0.3 grams
0.3 * 1 = 12 x
x = 0.3/12
x = 0.025 mol
1 mol of Carbon is 6.02 * 10^23 atoms
0.025 mol of carbon is x
1/0.025 = 6.02*10^23 * /x
x = 0.025 * 6.02 * 10^23
x = 1.5 * 10^22 atoms of carbon.