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2 years ago

What does Nb stand for on the periodic table? Pls help! Need aware soon

Chemistry

2 answers:

laila [671]2 years ago

7 0

It stands for niobium

Marina86 [1]2 years ago

4 0

It stands for niobium which was discovered in 1801 by Charles Hatchett of Brittan. It is ussed in welding rods, air fraim systems, superconductive magnets. It gets its name from iobe, the daughter of King Tantalus of the Greek myth. Niobium was considered identical to Tantalum, named after Tantalus, until 1884. Resists corrosin due to an oxide film. It is used in aviation industry

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What is the complete ionic equation for

murzikaleks [220]

Answer:

what is the net ionic equation

H2SO4(aq) + Cal2(aq) → CaSO4(s) + 2Hl(aq)?

A. H++ SO42- + Ca2+ + 21 → CaSO4 + H+ +1-

B. 2H+ + S042- + Ca2+ + 21° → Ca2+ + SO42- + 2H+ + 21

C. S042- + Ca2+ → CaSO4,

D. 2H+ + SO42- + Ca2+ + 2I- → CaSO4 + 2H+ + 2I-

cancel the spectator ion that is the ions which does not take place in the reaction

for this case is 2 H^+ and 2 i^-

5 0

2 years ago

Find the molarity of the following solutions: 0.5 moles of sodium chloride is dissolved to make 0.05 liters of solution.

vredina [299]

M(molarity)=moles/volume
M=.5mol/.05L=10M

4 0

2 years ago

Which term best describes what Donna observed?<br> A:dew<br> B:fog<br> C:mist <br> D:rain

MariettaO [177]

I also think it’s B but not quite sure

6 0

2 years ago

Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the

Olin [163]

Firstly we need to determine the partial pressure of O2:

$\begin{gathered} P_{O_2}=X\times P_T \\ P_{O_2}:partial\text{ }pressure \\ X:mole\text{ }fraction \\ P_T:total\text{ }pressure \\ \\ P_{O_2}=0.209\times0.35\text{ }atm \\ P_{O_2}=0.073\text{ }atm \end{gathered}$

We will now use the Henry's Law equation to determine the solubility of the gas:

$\begin{gathered} c=K_H\times P_{O_2} \\ c:solubility\text{ }or\text{ }concentration\text{ }of\text{ }the\text{ }gas(M) \\ K_H:Henry^{\prime}sLawconstant=3.7\times10^{-2}M\text{ }atm^{-1} \\ P_{O_2}:partial\text{ }pressure\text{ }of\text{ }the\text{ }gas=0.073atm \\ \\ c=3.7\times10^{-2}M\text{ }atm^{-1}\times0.073 \\ c=2.7\times10^{-3}M \end{gathered}$

Answer: Solubility is 2.7x10^-3 M

6 0

4 months ago

What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C

Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = $\frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\$

Now use the molar ratio to find how many moles of NaOH would be required to neutralize $5.5537*10^{-3} mol\\$ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

1 : 2 (we get this from the balanced equation)

$5.5537*10^{-3} mol\\$ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

$c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L$

5 0

3 years ago