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Sveta_85 [38]
2 years ago
15

Gavin was thinking of a number. Gavin adds 1, then divides by 7 to get an answer of -11. What was the original number?

Mathematics
1 answer:
grin007 [14]2 years ago
7 0

Answer:

The number Gavin was thinking of is -78.

Step-by-step explanation:

-78 +1= -77

-77/7 = -11

To solve I did:

-11 * 7

-77

-77-1= -78

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Heyy!! Can someone help me please!!
abruzzese [7]

Answer:

7x + 14

Step-by-step explanation:

the first thing to do is expand the parentheses/brackets.

3(5x + 2) -2(4x - 4) will be

3(5x) + 3(2) -2(4x) -2(-4)

= 15x + 6 - 8x + 8

collect like terms

15x - 8x + 6 + 8 = 7x + 14

the answer is 7x + 14

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A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e
ladessa [460]

Answer:

\frac{r(1-\sqrt{2})}{-3}

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

                          = \frac{1}{3} \pi r^{2} \times r

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Surface area of cone including 1 base = \pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}

Since r = h

So, area = \pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}

              = \pi r^{2} +\pi\times r \times \sqrt{2r^2}

              = \pi r^{2} +\pi\times r^2 \times \sqrt{2}

Ratio of volume of cone to its surface area including base :

\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}

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Rationalizing

\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}

\frac{r(1-\sqrt{2})}{-3}

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is \frac{r(1-\sqrt{2})}{-3}

8 0
3 years ago
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2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

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__

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In the year 2030, the population of kangaroos in the province is modeled to be 30.

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b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

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