All categories

2 years ago

If 10 people share 5 cookies , how much cookie does each person get

Mathematics

1 answer:

Pepsi [2]2 years ago

6 0

Answer:

1/2

Step-by-step explanation:

5 / 10 = 1/2

You might be interested in

What is 1/4 subtract 1 and 1/2 A. 1/2 B. 1/8 C. 3/4 D. 3/8

Lelu [443]

Answer:

-1 1/4

Step-by-step explanation:

1/4 - (1 1/2)

Get a common denominator

1/4 - 1 2/4

Take the larger number and subtract the smaller number and take the sign of the larger

1 2/4 - 1/4 = 1 1/4

The sign of the larger was negative

-1 1/4

3 0

3 years ago

NEED ANSWER FAST. 8th grade math

Kipish [7]

Answer: C

I can’t explain it very well, but the answer is C

6 0

3 years ago

Read 2 more answers

A train travels 95 kilometers in 1 hours, and then 97 kilometers in 1 hours. What is its average speed?

aleksandrvk [35]

Average speed is given by [Total Distance] ÷ [Total Time]

Average speed = $\frac{95+97}{1+1} = \frac{192}{2}=96$ km/hour

8 0

3 years ago

HELP ILL GIVE BRAINLISTTT!

olga nikolaevna [1]

Answer: √0.16

Step-by-step explanation:

√0.16 = 0.4

3 0

3 years ago

Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago