Answer:
B should be the answer but it could but C
Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:

Hence, the constant force exerted on the ball by the wall is 119.68 N.
Answer:
5 or 6
Step-by-step explanation:
Answer:
Negative numbers are used in navigation and directions determination
Answer:
g
Step-by-step explanation:
The maximum value occurs at gradient 0 (the stationary point).
In f this has a value (y) of 6.
In the equation example we have to differentiate:
dg(x)/dx = -x + 4
Gradient is 0 so 4 - x = 0 so x = 4
Plug g(4)=our maximum=-(1/2)4^2 + 4(4) + 3 = -8 + 16 + 3 = 11
11 > 6 so g has greater maximum.