All categories

2 years ago

Help plsssssssss <\3

Mathematics

1 answer:

kvv77 [185]2 years ago

7 0

Answer:

Step-by-step explanation:

$\frac{5}{5} + 6 = 1 + 6$

To solve this you just have to replace the letters with the corresponding numbers. 5/5 = 1 and 1+6 = 7

So your answer is 7!

You might be interested in

Autumn made 72 more cupcakes thsn Averle.If Autumn made 88 cupcakes how many did Averle make

saw5 [17]

Based on the number of cupcakes that Autumn made and the relationship to Averle, the number of cupcakes made by Averle was 16 cupcakes.

Autumn made 72 more cupcakes that the cupcakes made by Averle.

Autumn made 88 cupcakes which means that the number of cakes made by Averle must have been 72 less than this:

= 88 - 72

= 16 cupcakes

In conclusion, Averle made 16 cupcakes.

Find out more on this kind of operation at brainly.com/question/17829864.

5 0

2 years ago

DO I MULTIPLY (200 is 1/10) to get the correct answer of 2000 ?

Alexxx [7]

No that will equally 20.

Hope i helped :)

7 0

3 years ago

(b) What portion of the official U.S. poverty threshold (roughly $29,000 for a family of four) is met by the World Bank’s measur

otez555 [7]

World Bank's threshold for poverty is $1.25 per person per day.
For a family of four this gives:
Daily income = (number of people) * threshold
Daily income = 4 * $1.25
Daily income = $5
For a year this is:
Yearly income = (daily income) *365
Yearly income = $5 *365
Yearly income = $1825

U.S. poverty threshold is set at $29000. Portion of threshold can be calculated as:
$Portion\text{ }of\text{ }threshold= \frac{Poverty\text{ }threshold\text{ }(World\text{ }Bank)}{Poverty\text{ }threshold\text{ }(U.S.)} *100\% \\ \\ Portion\text{ }of\text{ }threshold= \frac{1825}{29000} *100\% \\ \\ Portion\text{ }of\text{ }threshold=6.29\%$

The poverty threshold measured by World Bank is 6.29% of the U.S. poverty threshold.

5 0

3 years ago

Does 23^-1 (mod 1000) exist? If yes solve it.

sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let x be the inverse. Then x is such that

23x ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for x :

1000 = 43×23 + 11

23 = 2×11 + 1

→ 1 ≡ 23 - 2×11 (mod 1000)

→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)

→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)

→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)

→ 23⁻¹ ≡ 87 (mod 1000)

3 0

3 years ago

What should be true about -5 and 5? Why?

Law Incorporation [45]

The thing that is true about -5 and 5 is the answer is zero.

5 0

3 years ago