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3 years ago

What multiplier would you use to decrease a value by 44%

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:

I think the answer is4k3+0 or 4

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What are the factors of the polynominal 2x+5x+3

My name is Ann [436]

Answer:

(7x+3)

Step-by-step explanation:

2x+5x+3 is simplified to 7x+3 which is the only factor of this binomial.

8 0

3 years ago

What is the limit of cosine as x approaches infinity?

sesenic [268]

Does not exist, since the graph of cosine is continuous between the intervals [-1,1]. You do not know where it will be when it “reaches” infinity

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3 years ago

Two angles of a quadrilateral measure 200° and 50°. The other two angles are in a ratio of 4:7. What are the measures of those t

Andrews [41]

Answer:

all angles will be 200, 50 , 40 and 70 - hope this helped :)

Step-by-step explanation:

everything equals to 360 after added together

360 - 250 = 110

110 divided by 11 = 10

4:7 (x 10)

40:70

the other angels will be 40 and 70

6 0

3 years ago

a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

<u>Taking power $\dfrac{1}{6}$ both side</u>

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

What’s the answer to this question

vichka [17]

Answer:

Step-by-step explanation:

8 0

3 years ago