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vazorg [7]
2 years ago
8

When a hydrocarbon burns in air what component of air reacts?

Chemistry
1 answer:
andre [41]2 years ago
5 0

Answer:

oxygen level reduces

Explanation:

because oxygen supports burning

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A bug travels at the rate of 3 miles/hours. How fast is this in um/nsec
sergij07 [2.7K]
Change units:

1 mile = 1609.34 m = 1609.34 * 10^6 micro m = 1.60934 * 10^9 m

1 hour = 3600 s = 3600 * 10^9 nano seconds = 3.6*10^12 nano sec

3 miles / hour = 3 * 1.60934 * 10^9 / (3.6*10^12) = 0.0013411 micro m/nano second = 1.3411*10^(-3) um / ns

Check it! Best

4 0
3 years ago
From each of the following pairs of substances, use data in Appendix E in the textbook to choose the one that is the stronger ox
dem82 [27]

Answer:

O3 is stronger oxidizing agent than  HO2-.

Cl2 is stronger oxidizing agent than I2.

Zn^2+ is stronger oxidizing agent than Co^2+.

Br2 is stronger oxidizing agent than BrO3-.

Explanation:

An oxidizing agent oxidizes other compound by undergoing reduction itself.

Gaining of electron or hydrogen is reduction.

1. O3 is stronger oxidizing agent than  HO2-. Because O3 readily gets decomposed into O2 and nascent (O), which oxidizes other compound. whereas as HO2- sometimes gets reduced to H2O2 and sometimes gets oxidized to O2.

2. Cl2 is stronger oxidizing agent than I2, as Cl2 can easily gain electrons compared to I2 due to its small atomic size.

3. Zn^2+ is stronger oxidizing agent than Co^2+, because Zn^2+ readily gains electrons compared toCo^2+ to form stable Zn due to its small atomic size.

4. Br2 is stronger oxidizing agent than BrO3-, as Br2 can accept electrons due to readily available empty orbitals compared to BrO3-.

6 0
3 years ago
How many grams of potassium chloride (KCI) are needed to prepare 0.750 L of a 1.50 M solution of potassium chloride in water?​
dedylja [7]
KCl: 74.5g/mol

Molarity = mol/Liters
Since you are given 0.750L and 1.50M, we can plug it into the molarity formula and solve for moles.

1.50M = x mol/0.750L
X = 1.125 moles of KCl needed

You asked for grams so let’s convert the moles of KCl to grams:

1.125 mol x (74.5g/mol) = 83.8g KCl
8 0
2 years ago
What is the molarity of a solution of 14.0 g NH4Br in enough H2O to make 150 mL of solution?
kiruha [24]
The molarity of a solution equals to the mole number of the solute/the volume of the solution. For NH4Br, we know that the mole mass is 98. So the molarity is (14/98) mol /0.15 L=0.95 mol/L.
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3 years ago
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