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Norma-Jean [14]
3 years ago
6

Characteristics of an atom

Chemistry
1 answer:
Doss [256]3 years ago
3 0

Answer:

It is composed of protons, which have a positive charge, and neutrons, which have no charge. Protons, neutrons, and the electrons surrounding them are long-lived particles present in all ordinary, naturally occurring atoms. Other subatomic particles may be found in association with these three types of particles.

Explanation:

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

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A standard room temperature and pressure, most of the elements on the periodic table are
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Answer:

Solids

Explanation:

At standard room temperature and pressure, most of the elements are solids.

Just a few of the elements are liquids and gases at this temperature.

The periodic table is made up of metals, metalloids and non-metals. Most of these substances are actually solid.

Some non-metals are gaseous at standard room temperature.

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otez555 [7]

Answer:

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3 years ago
Answer question number 6
Romashka [77]
It will be the first one
4 0
4 years ago
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Which of the following would force the reaction to favor the products? CaCO3(s) + 2H3O(aq) + Ca(aq) + 3H2O(1) + CO2(g) A) Removi
iVinArrow [24]

Answer: Option (C) is the correct answer.

Explanation:

As the given reaction is as follows.

     CaCO_{3}(s) + 2H_{3}O^{+}(aq) \rightleftharpoons Ca^{2+}(aq) + 3H_{2}O(l) + CO_{2}(g)

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

Hence, in order to favor the formation of products when we remove CO_{2} then there will occur decrease in it's concentration.

As CO_{2} is forming on the product side and equilibrium will shift in the direction where there is less stress.

Hence, then equilibrium will shift in the forward direction, that is, on the products side.

Thus, we can conclude that removing CO_{2} as it is formed would force the reaction to favor the products.

3 0
3 years ago
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Greeley [361]

Answer:

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3 0
4 years ago
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