Answer:
17.55 g of NaCl
Explanation:
The following data were obtained from the question:
Molarity = 3 M
Volume = 100.0 mL
Mass of NaCl =..?
Next, we shall convert 100.0 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
100 mL = 100/1000
100 mL = 0.1 L
Therefore, 100 mL is equivalent to 0.1 L.
Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:
Molarity = 3 M
Volume = 0.1 L
Mole of NaCl =?
Molarity = mole /Volume
3 = mole of NaCl /0.1
Cross multiply
Mole of NaCl = 3 × 0.1
Mole of NaCl = 0.3 mole
Finally, we determine the mass of NaCl required to prepare the solution as follow:
Mole of NaCl = 0.3 mole
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl =?
Mole = mass /Molar mass
0.3 = mass of NaCl /58.5
Cross multiply
Mass of NaCl = 0.3 × 58.5
Mass of NaCl = 17.55 g
Therefore, 17.55 g of NaCl is needed to prepare the solution.
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NOOOO NO thats not true at all
<span>Esters can be shown in text as: RCOOR or (occasionally) ROCOR.</span>
Answer:
There are 3.01x10²³ molecules of sucrose
Explanation:
In order to calculate the number of molecules of any atom or compound, we need to use the Avogadro number which is 6.02x10²³. This number could represent atoms or molecules of any mole of compound or atom.
In other words, 1 mole of a certain atom or compound has 6.02x10²³ molecules or atoms.
we have 0.5 moles of sucrose, all we just need to do is a simple rule of 3:
If 1 mole contains 6.02x10²³ molecules
then 0.5 moles will contain:
n° molecules = 0.5 * 6.02x10²³ / 1
<h2>
n° molecules = 3.01x10²³ molecules of sucrose</h2>
Hope this helps
