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Anettt [7]
2 years ago
5

During hybridization ______.

Chemistry
1 answer:
ANTONII [103]2 years ago
6 0

Answer:

option C two organisms with desired traits are bred

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150 units of chemical energy were converted into 35 units of thermal energy, 5 units of sound energy,
Mama L [17]
C

150=35+5+X
X= 150-(35+5)=150-40=110 /
7 0
3 years ago
How many moles of nitric acid are present in 50.0 g?
musickatia [10]

Answer:

3150.5g

Explanation:

1 mole of nitric acid weighs 63.01g

so i did 63.01g times 50.0g which equals 3150.5g

g= Grams

Hope This Helped

8 0
2 years ago
Read 2 more answers
How would you test to find out if<br> indigestion tablets are better than using<br> baking powder?
Orlov [11]
Go here and see how:
http://www.rsc.org/learn-chemistry/resource/res00000698/using-indigestion-tablets-to-neutralise-an-acid?cmpid=CMP00005978
7 0
4 years ago
The actual yield:
aleksley [76]

Answer:

rarely equals the theoretical yield

Explanation:

The actual yield is the result obtained from the experiment while the theoretical yield is the result obtained from our calculations. The actual yield of a chemical reaction rarely equals the theoretical yield because some of the amount are loss during the process.

4 0
3 years ago
When 0.300 g of a diprotic acid was titrated with 0.100 M LiOH, 40.0 mL of the LiOH solution was needed to reach the second equi
Iteru [2.4K]

Answer:

  • <em><u>H₂C₄H₄O₆</u></em>

Explanation:

The clue of this question is to find the molar mass of the <em>diprotic acid</em> and compare witht the molars masses of the choices' acid to identify the formula of the diprotic acid.

The procedure is:

  1. Find the number of moles of the base: LiOH
  2. Use stoichionetry to infere the number of moles of the acid.
  3. Use the formula molar mass = mass in grams / number of moles, to find the molar mass of the diprotic acid.
  4. Compare and conclude.

<u>Solution:</u>

<u>1. Number of moles of the base, LiOH:</u>

  • M = n / V in liter ⇒ n = M × V = 0.100 M × 40.0 ml × 1 liter / 1,000 ml = 0.004 mol LiOH.

<u>2. Stoichiometry:</u>

Since this a neutralization reaction of a diprotic acid with a mono hydroxide base (LiOH), the mole ratio at the second equivalence point is: 2 mol of base / 1 mole of acid; because each mole of LiOH releases 1 mol of OH⁻, while each mole of diprotic acid releases 2 mol of H⁺.

Hence, 0.004 mol LiOH × 1 mol acid / 2 mol LiOH = 0.002 mol acid.

<u>3. Molar mass of the acid:</u>

  • molar mass = mass in grams / number of moles = 0.300 g / 0.002 mol = 150. g/mol

<u>4. Molar mass of the possible diprotic acids:</u>

a. H₂Se: 2×1.008 g/mol + 78.96  g/mol = 80.976 g/mol

b. H₂Te: 2×1.008 g/mol + 127.6  g/mol = 129.616 g/mol

c. H₂C₂O₄ ≈ 2×1.008 g/mol + 2×12.011 g/mol + 4×15.999 g/mol ≈ 90.034 g/mol

d. H₂C₄H₄O₆ = 6×1.008 g/mol +  4×12.011 g/mol + 6×15.999 g/mol = 150.086 g/mol ≈ 150 g/mol.

<u>Conclusion:</u> since the molar mass of H₂C₄H₄O₆ acid is 150 g/mol, you conclude that is the diprotic acid whose 0.300 g were titrated with 40.0 ml of 0.100 M LiOH solution.

6 0
3 years ago
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