Fictitious element X has an a average atomic mass of 254.9 and only 2 isotopes, One of its isotopes has an abundance of 72.00 an
1 answer:
You might be interested in
Answer: The empirical formula for the given compound is
Explanation : Given,
Mass of O = 0.370 g
Mass of N = 0.130 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Oxygen =
Moles of Nitrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.
For Oxygen =
For Nitrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of O : N = 2 : 1
Hence, the empirical formula for the given compound is
Answer:
the energy vacancies for formation in silver is
Explanation:
Given that:
the equilibrium number of vacancies at 800 °C
i.e T = 800°C is 3.6 x 10¹⁷ cm3
Atomic weight of sliver = 107.9 g/mol
Density of silver = 9.5 g/cm³
Let's first determine the number of atoms in silver
Let silver be represented by N
SO;
where ;
avogadro's number =
= Density of silver = 9.5 g/cm³
= Atomic weight of sliver = 107.9 g/mol
N = 5.30 × 10²⁸ atoms/m³
However;
The equation for equilibrium number of vacancies can be represented by the equation:
From above; Considering the natural logarithm on both sides; we have:
Making the subject of the formula; we have:
where;
K = Boltzmann constant = 8.62 × 10⁻⁵ eV/atom .K
Temperature T = 800 °C = (800+ 273) K = 1073 K
Where;
1 eV = 1.602176565 × 10⁻¹⁹ J
Then
Thus, the energy vacancies for formation in silver is