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DochEvi [55]
3 years ago
5

Fictitious element X has an a average atomic mass of 254.9 and only 2 isotopes, One of its isotopes has an abundance of 72.00 an

d a mass of 250.9 amu. What is the atomic mass of the second isotope?
265.2

20.80

245.9

251.9

none of the above

all of the above
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

265.2amu

Explanation:

Given parameters:

Atomic mass  = 254.9amu

Abundance of isotope 1 = 72%

Atomic mass of isotope 1  = 250.9amu

Abundance of isotope 2  = 100  - 72  = 28%

Unknown:

Atomic mass of isotope 2 = ?

Solution:

To find the atomic mass of isotope 2, use the expression below:

Atomic mass = (abundance of isotope 1 x atomic mass of isotope 1) + (abundance of isotope 2 x atomic mass of isotope 2)

 Now insert the parameters and find the unknown;

  254.9  = (0.72 x 250.9)  + (0.28 x Atomic mass of isotope 2)

 254.9  = 180.648 + 0.28x atomic mass of isotope 2

 254.9 - 180.648  = 0.28x atomic mass of isotope 2

    74.25  = 0.28 x atomic mass of isotope 2

    Atomic mass of isotope 2 = 265.2amu

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Which is warmer -30C or -30 F?​
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How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

3 0
3 years ago
Which period does this atom belong to?
GrogVix [38]
I think it’s to long to fit in a period??
7 0
2 years ago
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