Answer:
280 mL
Explanation:
Given data:
Mass of CuSO₄ = 55.75 g
Molarity of CuSO₄ = 1.25 M
Volume of CuSO₄ = ?
Solution:
First of all we will calculate the number of moles.
Number of moles:
Number of moles = mass / molar mass
Number of moles = 55.75 g/ 159.6 g/mol
Number of moles = 0.35 mol
Volume of CuSO₄:
Molarity = number of moles / volume in litter
1.25 M = 0.35 mol / volume in litter
Volume in litter = 0.35 mol / 1.25 M
Volume in litter = 0.28 L
Volume in milliliter:
0.28 L × 1000 mL/ 1 L = 280 mL
Answer:
HAAAAA U IN SOME DEEP S***
Explanation:
The answer is: [A]: "<span>Osmosis occurs through a semipermeable membrane" .
____________________________________________________________</span>
Answer:
They are the smallest units of matter
Explanation:
Atom are the basic units of a chemical element; the smallest unit of an element that retains the properties of an element
Answer:
Density of solution = 1.43 g/mL
Molality → mol/kg = 37 m
Explanation:
The solute is HNO₃
Molar mass → 63 g/mol
70 % by mass → 70 g of solute / 100 g of solution
We convert the mass of HNO₃ to moles → 70 g / 63 g/mol = 1.11 moles
So let's apply molarity to find out the volume of our moles.
Molarity (M) = mol/L → mol / M = L → 1.11 mol / 15.9 M = 0.070 L
This is the volume for solution. We can convert it from L to mL
0.070 L . 1000 mL / 1L = 70 mL
As the mass of solution = 100 g → Density = Mass/Volume
100g / 70 mL = 1.43 g/mL
Molality → mol of solute / kg of solvent
Solution mass = 100 g → Mass of solute + Mass of solvent
Mass of solvent = 30 g
We convert the mass of solvent from g to kg → 30 g . 1kg / 1000 g = 0.030 kg
Molality (mol/kg) → 1.11 mol / 0.030 kg = 37 m
