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VikaD [51]
3 years ago
14

Calculate the molarity of 0.300 mol of Na2S in 1.75 L of solution.

Chemistry
1 answer:
Jobisdone [24]3 years ago
5 0
First equation:
molarity=
no.of moles of solute (Na2S)/volume of solution
0.300/1.75 = 0.171
second equation:
same law
but in volume it is milliliter so you have to convert it by multiplying it with 10^-3
(10 power -3)

to understand it clearly
see this
http://imgur.com/xTS35QM
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234+34.1 add and round to 2 significant figures
marin [14]
Like this? 234+34.1= 268.1 then round. If it is less than 5 then you round down if it is more then you round up. Because it is less the final number would be 268.1=268
3 0
3 years ago
Help me please !! How to solve it ??
snow_tiger [21]
1st one= CaO +H2O=Ca(OH)2
product side-
Ca=1
O=2
H=2
Reactant side-
Ca=1
O=2
H=2
The first one is balanced for you 
There is 1 calcium on each side 2 oxygens on each side and 2 hydrogens on each side


6 0
3 years ago
is the approximate relation celsius = 1/2 fahrenheit a better approximation at higher or lower temperatures?
kirill115 [55]

Answer : The approximate relation Celsius = 1/2 Fahrenheit is a better approximation at higher temperatures

Explanation :

The formula for Celsius to Fahrenheit conversion is

C = (F-32) \times \frac{5}{9}

At lower temperature the value that needs to be subtracted (32) is large enough as a result the approximation "celsius = 1/2 fahrenheit " does not seem valid.

For example, 50 F is 10°C.

(50 - 32) \times \frac{5}{9} = 10 C

This is almost 1/5 of Fahrenheit temperature.

But at higher temperatures , the value becomes insignificant and also the ratio  5/9 tend to be equal to 0.5.

For example, 2000 F is 1093°C

(2000 - 32) \times \frac{5}{9} = 1093 C

This is almost half of Fahrenheit temperature.

Therefore , the approximate relation Celsius = 1/2 Fahrenheit is a better approximation at higher temperatures

8 0
3 years ago
In which instance is a gas most likely to behave as an ideal gas?A.) At low temperatures, because the molecules are always far a
kiruha [24]

Answer:

C.) At room temperature and pressure, because intermolecular interactions are minimized and the particles are relatively far apart.

Explanation:

For gas to behave as an ideal gas there are 2 basic assumptions:

  • The intermolecular forces (IMF) are neglectable.
  • The volume of the gas is neglectable in comparison with the volume of the container.

<em>In which instance is a gas most likely to behave as an ideal gas?</em>

<em>A.) At low temperatures, because the molecules are always far apart.</em> FALSE. At low temperatures, molecules are closer and IMF are more appreciable.

<em>B.) When the molecules are highly polar, because IMF are more likely.</em> FALSE. When IMF are stronger the gas does not behave as an ideal gas.

<em>C.) At room temperature and pressure, because intermolecular interactions are minimized and the particles are relatively far apart.</em> TRUE.

<em>D.) At high pressures, because the distance between molecules is likely to be small in relation to the size of the molecules.</em> FALSE. At high pressures, the distance between molecules is small and IMF are strong.

3 0
3 years ago
What is the mass percentage of O in C₂H₄O₂? Provide an answer to two decimal places.
nasty-shy [4]

Answer:

53.29%

Explanation:

The molar mass of C2H4O2 is 60.05g and the 2 O's are 32.00g

so 32.00/60.05= 0.53288925895

and that as a decimal rounded to the nearest hundredths is 53.29%

6 0
2 years ago
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