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VikaD [51]
3 years ago
14

Calculate the molarity of 0.300 mol of Na2S in 1.75 L of solution.

Chemistry
1 answer:
Jobisdone [24]3 years ago
5 0
First equation:
molarity=
no.of moles of solute (Na2S)/volume of solution
0.300/1.75 = 0.171
second equation:
same law
but in volume it is milliliter so you have to convert it by multiplying it with 10^-3
(10 power -3)

to understand it clearly
see this
http://imgur.com/xTS35QM
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Answer:

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Explanation:

From the question given, we obtained the following data:

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We can obtain the empirical and molecular formula by doing the following as illustrated in the attached file. Please see attachment for explanation.

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Answer:<span>d. 145 minutes
</span>
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If 25.0% of the compound decomposes that means the final mass would be 75% of initial mass. Then the half-live for the compound would be:
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