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Assoli18 [71]
2 years ago
8

Help plz:

Mathematics
2 answers:
storchak [24]2 years ago
6 0

Answer:

Its A i do believe

Step-by-step explanation:

galben [10]2 years ago
5 0

Answer:

a.(x+5)(x-5) b.(y+6)(y-6) c.(x-1)(x+13) d. (s+2)(s+5)

Step-by-step explanation:

Sorry no step for c and d

for a 25 is a perfect square 5*5=25 -5*5=-25

for b it's same

sorry I'm rushing

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Use the given graph to determine the limit, if it exists. A
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Check the picture below.

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What is the value of the expression 2[3(4^2+1)]-2^3?
puteri [66]

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Step-by-step explanation: use photo math :)

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2 years ago
Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to
aivan3 [116]

ANSWER:

The surface area of the star is 3.2700 x 10^{8} square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x 10^{4} Km.

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Where n is the radius of the star.

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n = \frac{ 1.8083 * 10^{4} }{2}

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Thus,

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4 0
3 years ago
list the next nine multiples of each number Find the common multiples. Multiples of 4: 4, Multiples of 7:7, Common multiples: Mu
Alenkinab [10]
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4 : 4,8,12,16,20,24,28,32,36

7: 7,14,21,28,35,42,49,56,63

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6 0
3 years ago
Read 2 more answers
Somebody help me solve;
Nadya [2.5K]
P(at least 5 rolls until 1) = P(4 rolls are not 1) = 5/6 x 5/6 x 5/6 x 5/6 = 0.4823 (4sf)

Fewer than 7 rolls to get second 1 after first takes 3 rolls means second occurs on 4th, 5th or 6th roll
The probability of each of these is 1/6, 5/6 x 1/6 and 5/6 x 5/6 x 1/6 respectively.
P(second 1 on 4th, 5th or 6th roll) = 1/6 + 5/36 + 25/216 = 91/216 = 0.4213 (4sf)
3 0
2 years ago
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