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Irina-Kira [14]
2 years ago
6

Write an equation for the following graph

Mathematics
1 answer:
Anna [14]2 years ago
7 0
I do not see the graph.
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Solve the following equation. log(3x)=log(2x-4) *
Irina18 [472]

log(3x) = log(2x-4)

taking antilog of both sides:

3x = 2x - 4

3x - 2x = -4                    [subtracting 2x from both sides]

x = -4

and we're done already!

5 0
3 years ago
Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus
quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



5 0
3 years ago
Twelve more than a number is less than four.
Alenkasestr [34]

Answer:

n+12 <4

Step-by-step explanation:

4 0
3 years ago
1 + 1 I dont know how to solve this problem please help me...
Deffense [45]

Answer:

1+1= 2

Step-by-step explanation:

or sometimes people say 11, but irl its 2

4 0
3 years ago
100×0.23 = <br> 101×0.23 = <br> 102×0.23 = <br> 103×0.23 =
zaharov [31]

Answer:

100×0.23=23

101×0.23=23.23

102×0.23=23.46

103×0.23=23.69

7 0
2 years ago
Read 2 more answers
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