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OLEGan [10]
3 years ago
10

a 12000.0-kg car is traveling at 19 m/s. the driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic

friction between the tires and the road is 0.80. for what length of time is the car skidding?
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
What I don’t get it ?
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3. A -4.00-uC charge lies 20.0cm to the right of a 2.00-uC charge on the x axis. What is the force on the 2.00-uC charge?
Sladkaya [172]

<u>Answer:</u>

The force on the 2.00-uC charge is 36 \times 10^{10} \mathrm{N}

<u>Explanation:</u>

We know that force between two charges is given by Coulomb’s law,

\mathrm{F}=\mathrm{k} \frac{q 1 q 2}{r * r}

Where k = Coulomb’s constant =

9.0 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2}

And q1 and q2 are the charges given to be = -4.00-uC and 2.00-uC charges

And r = distance between the charges = 20 cm = 0.2 m  

Substituting the given values in the formula we get force applied on 2.00\ \mu C charge,

F =  36 \times 10^{10} \mathrm{N} attractive force which is the required answer.

3 0
3 years ago
What information is necessary to calculate a confidence interval?
Anni [7]
<span>Write down the phenomenon you'd like to test. ...Select a sample from your chosen population. ...Calculate your sample mean and sample standard deviation. ...Choose your desired confidence level. ...Calculate your margin of error. ...<span>State your confidence interval.</span></span>
6 0
3 years ago
Which organism in the food chain is sometimes first level consumer and sometimes 2nd level
makkiz [27]
I believe the answer is Mouse/Herbivore. It was a question in my old lab haha.

Hope this helped!!
~xox Melis
7 0
3 years ago
A single brick falls with acceleration g. The reason a double brick falls with the same acceleration is
LekaFEV [45]

The reason is because the force due to the acceleration from gravity is constant. It's the same as the typical "dropping a bowling ball and feather (with no air resistance) at the same time". Gravity acts on all object with the same acceleration regardless of physical properties.

5 0
3 years ago
Read 2 more answers
A water pipe tapers down from an initial radius of R1 = 0.21 m to a final radius of R2 = 0.11 m. The water flows at a velocity v
Aleks [24]

Answer:

0.116 m^3/s

Explanation:

The volume flow rate of a fluid in a pipe is given by:

Q=Av

where

A is the cross-sectional area of the pipe

v is the speed of the fluid

In this problem, at the initial point we have

v = 0.84 m/s is the speed of the water

r = 0.21 m is the radius of the pipe, so the cross-sectional area is

A=\pi r^2 = \pi (0.21 m)^2 =0.138 m^2

So, the volume flow rate is

Q=(0.138 m^2)(0.84 m/s)=0.116 m^3/s

8 0
3 years ago
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