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2 years ago

Please look at the photo and give me the answer :)))

Physics

1 answer:

san4es73 [151]2 years ago

5 0

Answer:

Explanation:

efficiency is measured in % hence 0.02% is smaller than 20%

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2 years ago

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The driver of a 1000 kg car traveling at a speed of 16.7 m/s applies the brakes. If the brakes provide a force of - 8000 N to st

RSB [31]

Answer:

Given:

m=1000kg

u= 16.7m/s

v=0m/s

F=8000N

Required:

s=?

Solution:

F=m × a

8000N=1000kg × a

a=8m/s^2

Since it decelerate a= -8m/s^2

v^2 = u^2 + 2as

s=v^2 - u^2 / 2a

s= 0 - (16.7m/s)^2 / 2 × -8m/s^2

s= -278.89/-16

s= 17.43m

The car travels approximately 17.43m before it stops

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1 year ago

wo fixed charges, A and B are located at x axis. A is at x = 0 m, B is at x = 4 m. QA = +4.0 μC and QB = -5.0 μC. Calculate the

lys-0071 [83]

Answer:

10250 N/C leftwards

Explanation:

QA = 4 micro Coulomb

QB = - 5 micro Coulomb

AP = 6 m

BP = 2 m

A is origin, B is at 4 m and P is at 6 m .

The electric field due to charge QA at P is EA rightwards

$E_{A}=\frac{KQ_{A}}{AP^{2}}=\frac{9\times10^{9}\times4\times10^{-6}}{6^{2}}=1000 N/C (rightwards)$

The electric field due to charge QB at P is EB leftwards

$E_{B}=\frac{KQ_{B}}{BP^{2}}=\frac{9\times10^{9}\times5\times10^{-6}}{2^{2}}=11250 N/C (leftwards)$

The resultant electric field at P due the charges is given by

E = EB - EA

E = 11250 - 1000 = 10250 N/C leftwards

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3 years ago

What is refraction? this my in sta id-:akhilrawat9453

My name is Ann [436]

Explanation:

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2 years ago

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Why is MA always less than VR?

jarptica [38.1K]

Answer:

$\boxed{ \bold{ \boxed{ \sf{see \: below}}}}$

Explanation:

MA ( Mechanical Advantage ) is always less than VR ( Velocity Ratio ) because MA is reduced by friction but VR is not affected by friction.

Hope I helped!

Best regards! :D

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3 years ago