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2 years ago

Which correctly lists three items that are removed during the purification of wastewater?

Chemistry

2 answers:

PSYCHO15rus [73]2 years ago

8 0

Answer:

gases, debris, groundwater.

Explanation:

if I'm wrong blame me.

hope it helps.

and can I have briniest

kotegsom [21]2 years ago

3 0

Answer: its the 3rd one

Explanation:

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The empirical formula of a compound of iron (Mg) and sulfur (S) was determined using the following data. A sample of Mg was weig

Fudgin [204]

Answer:

The empirical formula is MgS

The number of moles Mg is 0.25 moles

There will react 0.25 moles

Option A is correct

Explanation:

Step 1: data given

The molecular weight of Mg = 24.305 g/mol

The molecular weight of S is 32.065 g/mol

mass of crucible and cover = 27.631 grams

mass of crucible, cover and Mg = 33.709 grams

mass of crucible, cover, and the compound formed 41.725 grams

Step 2: Calculate mass of Mg

Mass of Mg = mass of crucible, cover and Mg - mass of crucible and cover

Mass of Mg = 33.709 grams - 27.631 grams

Mass of Mg = 6.078 grams

Step 3: Calculate moles Mg

Moles Mg = mass Mg / atomic mass Mg

Moles Mg = 6.078 grams 24.305 g/mol

Moles Mg = 0.250 moles

Step 4: Calculate mass compound

Mass compound = mass of crucible, cover, and the compound formed - mass of crucible and cover

Mass compound = 41.725 grams - 27.631 grams

Mass compound = 14.094 grams

Step 5: Calculate mass sulfur

Mass sulfur = 14.094 grams - 6.078 grams

Mass sulfur = 8.016 grams

Step 6: Calculate moles Sulfur

Moles sulfur = 8.016 grams / 32.065 g/mol

Moles sulfur = 0.250 moles

Step 7: Calculate the mol ratio

We diviide by the smallest amount of moles

Mg: 0.250 moles / 0.250 moles = 1

S: 0.250 moles / 0.250 moles = 1

The empirical formula is MgS

The number of moles Mg is 0.25 moles

There will react 0.25 moles

Option A is correct

4 0

3 years ago

Read 2 more answers

the pressure in a sealed plastic container is 108 kPa at 41 degrees Celsius. What is the pressure when the temperature drops to

Katarina [22]

Answer: The new pressure will be 101.46 kPa.

Explanation:

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1\text{ and }T_1$ are initial pressure and temperature.

$P_2\text{ and }T_2$ are final pressure and temperature.

We are given:

By using conversion factor: $T(K)=T(^oC)+273$

$P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K$

Putting values in above equation, we get:

$\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa$

Hence, the new pressure will be 101.46 kPa.

3 0

3 years ago

Determine the frequency and wavelength (in nm) of the light obsorded when the e- goes from n=1 to n=5

morpeh [17]

Answer:

Frequency = 3.16 ×10¹⁴ Hz

λ = 0.95×10² nm

Explanation:

Energy associated with nth state is,

En = -13.6/n²

For n = 1

E₁ = -13.6 / 1²

E₁ = -13.6/1

E₁ = -13.6 ev

Kinetic energy of electron = -E₁ = 13.6 ev

For n = 5

E₅ = -13.6 / 5²

E₅ = -13.6/25

E₅ = -0.544 ev

Kinetic energy of electron = -E₅ = 0.544 ev

Wavelength of radiation emitted:

E = hc/λ = E₅ - E₁

hc/λ = E₅ - E₁

by putting values,

6.63×10⁻³⁴Js × 3×10⁸m/s / λ = -0.544ev - (-13.6 ev )

6.63×10⁻³⁴ Js× 3×10⁸m/s / λ = 13.056 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s /13.056 ev

λ = 6.63×10⁻³⁴ Js× 3×10⁸m/s /13.056 × 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 13.056 × 1.6×10⁻¹⁹ J

λ = 19.89 ×10⁻²⁶ Jm / 20.9 ×10⁻¹⁹ J

λ = 0.95×10⁻⁷ m

m to nm:

0.95×10⁻⁷ m ×10⁹nm/1 m

0.95×10² nm

Frequency:

Frequency = speed of electron / wavelength

by putting values,

Frequency = 3×10⁸m/s /0.95×10⁻⁷ m

Frequency = 3.16 ×10¹⁴ s⁻¹

s⁻¹ = Hz

Frequency = 3.16 ×10¹⁴ Hz

4 0

3 years ago

You get a can of soda from the vending machine and your “friend” maliciously shakes it when you’re not looking. You open the can

vaieri [72.5K]

Physical Change because a new substance was not created and if it was a chemical change, a new substance would have to be created.

8 0

4 years ago

Read 2 more answers

What is the name of this hydrocarbon?

Deffense [45]

Answer:

1-Fluoro-4-nitrobenzene

Step-by-step explanation:

Step 1. Identify the substituents on the ring,

The groups are fluoro and nitro. They have no priority as functional groups, so the base name is benzene.

Step 2. Identify their relative priorities.

F and NO₂ have no functional group priority, so we list them in alphabetical order. F has alphabetical priority over NO₂. The name becomes fluoronitrobenzene.

Step 3. Number the atoms of the ring.

The C atom bearing the F is C1. Count around the ring, and the NO₂ group is on C4.

Step 4. Name the compound.

Insert the locating numbers immediately in front of the substituents. Use hyphens to join letters to numbers.

The name becomes 1-fluoro-4-nitrobenzene.

7 0

4 years ago