Answer:
![Impulse = 8.0Ns](https://tex.z-dn.net/?f=Impulse%20%3D%20%208.0Ns)
Explanation:
Given
![Force = 80.0N](https://tex.z-dn.net/?f=Force%20%3D%2080.0N)
![Mass = 0.25kg](https://tex.z-dn.net/?f=Mass%20%3D%200.25kg)
![Time = 0.10s](https://tex.z-dn.net/?f=Time%20%3D%200.10s)
Required
Determine the impulse
The impulse is calculated as follows:
![Impulse = Force * Time](https://tex.z-dn.net/?f=Impulse%20%3D%20%20Force%20%2A%20Time)
Substitute values for Force and Time
![Impulse = 80.0N * 0.10s](https://tex.z-dn.net/?f=Impulse%20%3D%20%2080.0N%20%2A%200.10s)
![Impulse = 8.0Ns](https://tex.z-dn.net/?f=Impulse%20%3D%20%208.0Ns)
<em>Hence, the impulse experienced is 8.0Ns</em>
Answer:
Potential energy = 3635.8 Joules
Explanation:
Given that,
Weight lifted by a weight lifter is 12 kg
It lifts to a height of 1.75 m
We need to find the potential energy to the wights now have. The energy possessed by an object due to its position or height above ground is called potential energy. Its formula is given by :
P = mgh
g is the acceleration due to gravity
![P=212\ kg\times 9.8\ m/s^2\times 1.75\ m\\\\P=3635.8\ J](https://tex.z-dn.net/?f=P%3D212%5C%20kg%5Ctimes%209.8%5C%20m%2Fs%5E2%5Ctimes%201.75%5C%20m%5C%5C%5C%5CP%3D3635.8%5C%20J)
So, the potential energy is 3635.8 joules.
Electric field is defined as force per unit charge.
So it is given by
![F = q E](https://tex.z-dn.net/?f=F%20%3D%20q%20E)
now we can find electric field by
![E = \frac{F}{q}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BF%7D%7Bq%7D)
![E = \frac{4.5*10^{-4}}{6 * 10^{-4}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B4.5%2A10%5E%7B-4%7D%7D%7B6%20%2A%2010%5E%7B-4%7D%7D)
![E = 0.75 N/C](https://tex.z-dn.net/?f=E%20%3D%200.75%20N%2FC)
So field strength is 0.75 N/C.
Answer:
if its winter
Explanation:
then we know it will me cold