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adelina 88 [10]
3 years ago
9

How much power is needed to lift the 200-N object to a height of 10 m in 4 s?

Physics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

500 watts

Explanation:

Recall that the definition of power is the amount of energy delivered per unit of time.

In our case, the energy delivered is potential energy which we can estimate as the product of the weight of the object times the distance it is lifted above ground:

200 N x 10 m = 2000  Nm

then the power is the quotient of this potential energy divided the time it took to lift the object to that position:

Power = 2000 / 4   Nm/s = 500 Nm/s = 500 watts

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ExtremeBDS [4]

Answer:

B. 14.4 N

Rotational speed (Angular Velocity) = 2

The Radius of the circle = 1.2 m

Velocity = Angular velocity × radius = 2×1.2 = 2.4 m/s

Centripetal force= mv²/r = 3 × 2.4×2.4/1.2 = 3 × 2.4 × 2

= 14.4 N

7 0
3 years ago
A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in
Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

d_x = 3.65-1.91=1.74 m

While the displacement in the y-direction is:

d_y = -4.79 -(-2.73)=-2.06 m

The time taken is t = 304 s.

So the components of the average velocity are:

v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s

v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s

And the magnitude of the average velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s

8 0
3 years ago
A block of lead has dimensions of 4.50 cm by 5.20 cm by 6.00 cm. The block weighs 1587 g. From this information, calculate the d
mamaluj [8]

Answer:

11.3 g/cm^3

Explanation:

density = mass/volume

volume of rectangular prism = length * width * height

volume = (4.50 cm)(5.20 cm)(6.00 cm) = 140.4 cm^3

mass = 1587 g

density = (1587 g)/(140.4 cm^3)

density = 11.3 g/cm^3

6 0
3 years ago
A 4-m long wire with a mass of 40 g is under tension. A transverse wave for which the frequency is 860 Hz, the wavelength is 0.5
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Answer:

Maximum acceleration will be 195372m/sec^2    

Explanation:

It is given mass m =40 gram = 0.04 kg

Length of the wire l = 4 m

Frequency of transverse wave f = 860 Hz

Wavelength \lambda =0.5m

Amplitude of the propagating wave A=6.7mm=0.0067m

Angular frequency is equal to \omega =2\pi f=2\times 3.14\times 860=5400rad/sec

Maximum acceleration is equal to a=\omega ^2A=5400^2\times 0.0067=195372m/sec^2

So maximum acceleration will be 195372m/sec^2

4 0
3 years ago
You want to design a spy bracelet that can send a signal to a friends bracelet when you are nearby. which type of electromagneti
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