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3 years ago

How much power is needed to lift the 200-N object to a height of 10 m in 4 s?

Physics

1 answer:

harkovskaia [24]3 years ago

6 0

Answer:

500 watts

Explanation:

Recall that the definition of power is the amount of energy delivered per unit of time.

In our case, the energy delivered is potential energy which we can estimate as the product of the weight of the object times the distance it is lifted above ground:

200 N x 10 m = 2000 Nm

then the power is the quotient of this potential energy divided the time it took to lift the object to that position:

Power = 2000 / 4 Nm/s = 500 Nm/s = 500 watts

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Metal conducts heat quicker than wood or air so when you touch it heat is taking away from you body faster than when you touch the wood desk. When heat is taken from our bodies our brain interprets this as cold.

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3 years ago

A car travels at a constant velocity of 70 mph for one hour. At the second hour, the car’s velocity was 60 mph. At the third hou

katovenus [111]

When the velocity increases, then the acceleration will be positive and when the velocity decrease then the acceleration will be negative.

During the first hour, the velocity was 70 mph and during the seconds hour the velocity was 60 mph. Hence, the velocity decrease in the seconds hour. So, the acceleration will be negative during the second hour.

Now, during the third hour the velocity increases as it is 80 mph. Hence, the acceleration will be positive during the third hour.

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3 years ago

Read 2 more answers

A container with volume 1.83 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas

alisha [4.7K]

Answer:

The pressure is $P = 1652 \ Pa$

Explanation:

From the question we are told that

The volume of the container is $V = 1.83 \ L = 1.83 *10^{-3 } \ m^3$

The mass of $N_2$ is $m_n = 0.246 \ g = 0.246 *10^{-3} \ kg$

The root-mean-square velocity is $v = 192 \ m/s$

The root -mean square velocity is mathematically represented as

$v = \sqrt{ \frac{3 RT}{M_n } }$

Now the ideal gas law is mathematically represented as

$PV = nRT$

=> $RT = \frac{PV}{n }$

Where n is the number of moles which is mathematically represented as

$n = \frac{ m_n }{M }$

Where M is the molar mass of $N_2$

$RT = \frac{PVM_n }{m _n }$

=> $v = \sqrt{ \frac{3 \frac{P* V * M_n }{m_n } }{M_n } }$

=> $v = \sqrt{ \frac{ 3 * P* V }{m_n } } }$

=> $P = \frac{v^2 * m_n}{3 * V }$

substituting values

=> $P = \frac{( 192)^2 * 0.246 *10^{-3}}{3 * 1.83 *10^{-3} }$

=> $P = 1652 \ Pa$

3 0

3 years ago

A toy of mass 0.190-kg is undergoing SHM on the end of a horizontal spring with force constant k = 350 N/m . When the toy is a d

vagabundo [1.1K]

Answer

a)0.0495 J

b)0.01681 m

c)0.7218 m/s

Explanation:

Given

Mass of the.toy M = 0.190 kg

force constant k = 350 N/m

Displacement from equilibrium x = 0.0140 m

Speed v = 0.400 m/s

a)What is the toy's total energy at any point of its motion?

The total energy at any point of it's motion can be calculated by adding together both the potential and kinetic energy of the toy, since it's posses potential energy when at rest and kinetic energy at motion

Total energy E = kinetic energy + potential energy

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.190)(0.4)² + ¹/₂ (350)(0.0140)²

E = 0.0495 J

Hence,the total energy is 0.0495 J

b) the amplitude of the motion can be calculated using below formula

Let amplitude = A

E = ¹/₂KA²

if we make Amplitude A the subject of the formula we have

A=√(2E/k)

But we have calculated our E up there, our K was given in question then if we substitute we have

A= √(2×0.0495)/350

Ans: 0.01681 m

Hence, our Amplitude is 0.01681 m

c) the the toy's maximum speed during its motion can be calculated using the expression below

Let maximum speed = vmax

E = (1/2)M * vmax^2

If we make vmax the subject of the formula we have

vmax =√(2E/m)

vmax= √(2×0.0495)/0.190

vmax=0.7218 m/s

Hence our vmax is 0.7218 m/s

8 0

3 years ago

An alligator swims to the left with a constant velocity of 5 \,\dfrac{\text{m}}{\text s}5

dexar [7]

Answer:

The alligator will take t = 10 s to reach the final speed of 35 m/s

Explanation:

As we know that the initial speed of the alligator is 5 m/s

then it accelerate by given acceleration to reach the final speed of 35 m/s

so we will have

$v_i = 5 m/s$

$v_f = 35 m/s$

$a = 3m/s^2$

now we have

$v_f = v_i + at$

$35 = 5 + 3 t$

$t = 10 s$

5 0

3 years ago