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adelina 88 [10]
2 years ago
9

How much power is needed to lift the 200-N object to a height of 10 m in 4 s?

Physics
1 answer:
harkovskaia [24]2 years ago
6 0

Answer:

500 watts

Explanation:

Recall that the definition of power is the amount of energy delivered per unit of time.

In our case, the energy delivered is potential energy which we can estimate as the product of the weight of the object times the distance it is lifted above ground:

200 N x 10 m = 2000  Nm

then the power is the quotient of this potential energy divided the time it took to lift the object to that position:

Power = 2000 / 4   Nm/s = 500 Nm/s = 500 watts

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Compare the speed of light in water to the speed of sound in water
kakasveta [241]

Answer:As a rule sound travels slowest through gases,faster through liquids,and fastest through solids.The speed of light as it travels through air and space is much faster than that of sound; it travels at 300 million meters per second or 273,400 miles per hour.Speed of light in water = 226 million m/s or 205,600 mph.

Explanation:dont have one

6 0
3 years ago
How do u calculate momentum
Helga [31]

Answer:

Explanation:

To calculate the momentum of a moving object multiply the mass of the object times its velocity. The symbol for momentum is a small p. So, the momentum of the object is calculated to be 8.0 kg-m/s. Note the unit for momentum.

5 0
3 years ago
If the sun is scaled down to 9.5 inches in diameter, the earth would be about _____ inches in diameter
vovangra [49]

Answer: 0.087 inches

Explanation:

This problem can be solved applying the <u>Rule of three</u>, which is a  mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this sense, the actual diameter of the Sun is 1,391,020 km and the actual diameter of the Earth is 12,742 km.

Now, applying the <u>Rule of three:</u>

<u />

Sun 1,391,020 km ------ 9.5 inches

Earth 12,742 km --------- ? inches

? inches=\frac{(12,742 km)(9.5 inches)}{1,391,020 km}

? inches=0.087 inches

Therefore:

If the sun is scaled down to 9.5 inches in diameter, the earth would be about <u>0.087 inches </u>in diameter.

7 0
3 years ago
Let's assume you use green light (λ = 550 nm) to look at an electron. What is the uncertainty in determining the electron's velo
Rudiy27
By uncertainty principle

λ = h / p.         

Where λ = wavelength,  h = Planck's constant = 6.63 * 10⁻³⁴ Js

λ = wavelength = 550 nm = 550 * 10⁻⁹ m, Mass of electron = 9.1 * 10 ⁻³¹ kg

p = Momentum = mv

λ = h / mv

v = h / mλ

v = 6.63 * 10⁻³⁴ / (9.1 * 10⁻³¹ *  550 * 10⁻⁹)

v = 1 324 675.325 m/s

v ≈ 1.325 *10⁶  m/s
8 0
3 years ago
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