Answer:a= 2.5 b=3.5 c= 0.1036 d=3 e=150
Explanation:
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The given question lacks the choices, however, the correct question with choices are:
hydrochloric acid is a strong acid. acetic acid is a weak acid. which statement about hydrochloric acid and acetic acid is correct?
- a. If the initial concentration of each acid is the same, then acetic acid will produce more H, 3, O, +, ions than hydrochloric acid..
- b. A solution of hydrochloric acid at equilibrium will have a greater concentration of solute than a solution of acetic acid at equilibrium.
- c. The pH of a solution of hydrochloric acid must be less than the pH of a solution of acetic acid.
- d. The dissociation constant for hydrochloric acid is greater than the dissociation constant for acetic acid.
The correct statement about hydrochloric acid and acetic acid is: D. The dissociation constant for hydrochloric acid is greater than the dissociation constant for acetic acid.
Acid strength is the ability of an acid to dissociate into a proton and an anion. The extent of dissociation of an acid in solution is shown by the dissociation constant.
- A strong acid splits or ionizes to completely or totally dissociates in a water solution
- A weak acid occasionally dissociates in a water solution.
Thus, The correct statement about hydrochloric acid and acetic acid is: D. The dissociation constant for hydrochloric acid is greater than the dissociation constant for acetic acid.
Learn more about the strength of an acid:
brainly.com/question/3223615
A have risen about 40 percent beyond cost of living in the last two decades
Answer:
x/ y = -2/ 3
Explanation:
we have:
3(x + y) = y
<em>distributing</em><em> </em><em>3</em><em> </em><em>within</em><em> </em><em>the</em><em> </em><em>parenthesis</em><em>:</em>
<em>=</em><em>></em><em> </em>3x + 3y = y
<em>taking y to the other side, changing its sign in the process</em>
=> 3x = y - 3y
=> 3x = y(1 - 3)
=> 3x = -2y
<em>you</em><em> </em><em>can</em><em> </em><em>represent</em><em> </em><em>any</em><em> </em><em>integer</em><em> </em><em>as</em><em> </em><em>a</em><em> </em><em>fraction</em><em> </em><em>by</em><em> </em><em>putting</em><em> </em><em>a</em><em> </em><em>"</em><em>1</em><em>"</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>denominator</em>
<em>taking</em><em> </em><em>y</em><em> </em><em>to</em><em> </em><em>th</em><em>e</em><em> </em><em>denominator</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>LHS</em><em> </em><em>and</em><em> </em><em>3</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>denominator</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>RHS</em>
that makes the ratio, x/y = -2/ 3
______________
Hope this helps!