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Zigmanuir [339]
3 years ago
5

Find all the perfect cubes between 1000 and 2000.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
There are only 2 perfect cubes in between 1000 and 2000.

11^3 = 1331
12^3 = 1728
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Write down the possible values of x.x is an interger.
Simora [160]

Answer:

-1, 0, 1, 2, 3

Step-by-step explanation:

To answer this you have to understand 2 main things

These are: the symbols and what an integer is.

An integer is simply a whole number. For example: 1, 10, 3 etc.

The symbols, <= (first symbol) and < (second symbol) are very important. These tell us the range X is in.

<= means less than or equal to.

< means less than.

So we can write: -1 is less than or equal to x and x is less than 4.

If we follow this and also keep in mind we only want whole numbers then we can see the lowest X can be is -1 and the highest it can be is 3 since it has to be less than 4.

Then it is also everything inbetween them which is:

-1, 0, 1, 2, 3

5 0
3 years ago
I need help an trash at math
Vlada [557]

Answer:

i believe its 16

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Pls answer this..........
Paul [167]

Answer:

b.

Step-by-step explanation:

6 0
4 years ago
Rewrite as a logarithmic equation. e^9=y
kolbaska11 [484]
Log y=9.
e


Drop first and make it logs base.
Y sits beside it
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4 0
4 years ago
(10 points) From a group of 9 men and 7 women a committee consisting of 4 men and 4 women is to be formed. How many different co
alexgriva [62]

Answer:

a) 2450

b) 1890

c) 1050

Step-by-step explanation:

Given:

- Available Group = 9 M & 7 F

- Committee of= 4 M and 4 W to be formed

Find:

- (a) 2 of the men refuse to serve together?

- (a) 2 of the women refuse to serve together?

- (a) 1 man and 1 woman refuse to serve together?

Solution:

- The question pertains to a selection process, We will use combinations for each case as follows.

part a)

- Since 2 men cant be selected together. Then we have to discount for one man while selecting Man for the committee. Hence, the combinations are:

                                   8C4 x 7C4 = 2450

part b)

- Since 2 women cant be selected together. Then we have to discount for one woman while selecting them for the committee. Hence, the combinations are:

                                   9C4 x 6C4 = 1890

part b)

- Since 1 women and a man cant be selected together. Then we have to discount for one woman and one man while selecting them for the committee. Hence, the combinations are:

                                   8C4 x 6C4 = 1050

4 0
4 years ago
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