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miv72 [106K]
3 years ago
5

A 39-kg girl is bouncing on a trampoline. During a certain interval after leaving the surface of the trampoline her kinetic ener

gy decreases to 160 J from 490 J. How high does she rise during this interval? Neglect air resistance.
Physics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

The distance is 0.86 m.

Explanation:

Given that,

Mass = 39 kg

Initial kinetic energy, K.E_{i} = 160\ J

Final kinetic energy, K.E_{f} = 490\ J

We need to calculate the work done

According to work energy theorem

W = \Delta K.E

W=K.E_{f}-K.E_{i}...(I)

Work done is the product of the force and displacement.

W = mgh....(II)

From equation (I) and (II)

K.E_{f}-K.E_{i}=mgh

490-160=39\times9.8\times h

h = 0.86\ m

Hence, The distance is 0.86 m.

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