We want to answer different things about the weight of the dogs, with simple algebra we will find that the answers are:
- a) P - 13lb + 1.2*E = P - 1lb
- b) E = 10lb
- c) Euclid's weight is 10 pounds.
- d) Pythagora's weight is 33 pounds and Riemann's weight is 20 pounds.
We start by defining the two variables we will be using:
- E = Euclid's weight
- P = Pythagoras's weight
First, Pythagoras loses 13 lb, then his new weight is:
P' = P - 13lb
We know that if he wins 1.2 Euclid's weight, he will still have a pound less than before.
A) using the above information we can rewrite:
P - 13lb + 1.2*E = P - 1lb
This is the equation we need to solve.
b) So we want to solve this for E, then we move all the other terms to the right side:
1.2E = P - 1lb - P + 13lb
1.2E = 12lb
E = (12lb)/1.2 = 10lb
c) The solution of the above equation tells us that the weight of the dog is 10lb.
d) Let's define R as the weight of the third dog.
We know that:
R = 2*E = 2*10lb = 20lb
We also know that the combined weight of the 3 dogs is 63 lb, then we have:
E + R + P = 63lb
10lb + 20lb + P = 63lb
P = 63lb - 10lb -20lb = 33lb
If you want to learn more about algebra, you can read:
brainly.com/question/20607627
