Question

820 mol of hydrogen gas hydrogen gas has a volume of 2.00 l at a certain temperature and pressure. what is the volume of 0.125 mol of this gas at the same temperature and pressure

Answer 1

 To solve this problem, let us first assume that the hydrogen gas acts like an ideal gas. So that we can make use of the ideal gas equation:

P V = n R T

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the absolute temperature

Since it is given that T and P is constant therefore we can write the equation as:

V / n = k

So equating the two conditions:

V1 / n1 = V2 / n2

We can now solve for the new V2 given n2 = 0.125:

2 L / 820 mol = V2 / 0.125 mol

V2 = 3.05 x 10^-4 L

The new volume is about 3.05 x 10^-4 L which is equivalent to 0.3 mL