Answer:
The maximum electric field strength is 0.0144 V/m.
Explanation:
Given that,
Electric potential created in the heart, V = 3.6 mV
Distance, d= 0.25 m
Frequency of the the electromagnetic wave, f = 1 Hz
We need to find the maximum electric field strength created. We know that the electric potential is given by :

E is the maximum electric field strength

So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.
At the position of terminal speed the net acceleration of the ball will become zero
As we know that terminal speed will always reach when net force on the ball is zero and its speed will become constant.
So here at this position we can say



now when ball is moving at half of the terminal speed in upward direction then net force on the ball in downwards direction will be


here speed of the ball is half of the terminal speed

then we have


now acceleration will be given as

now we have

downwards
Answer:
W = Q * V work done on charge Q
A. W = .5 C * 1.5 V = .75 Joules
B. P = W / t = .75 J / 1 sec = .75 Watts
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