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LenaWriter [7]
3 years ago
8

What is the kinetic energy of a 4 kg toy car moving at 5 m/s?

Physics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:

50 J

Explanation:

<3

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As you run , your feet push on the ground with a force 500N . The ground pushes back on your feet with a force of 500N . (Please
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true

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newtons third law says to every action there is always an equal and opposite reaction. so the answer is true

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What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force?
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3 years ago
A basketball player is running at 5.00 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains
makkiz [27]

Answer:

3.834 m/s

Explanation:

h = 0.750 m

vx = 5 m/s

Let the initial vertical velocity is vy.

Final vertical velocity is zero

use third equation of motion along y axis

v^2 = vy^2 - 2 x g x h

0 = vy^2 - 2 x 9.8 x 0.75

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4 years ago
the second question. the answer to the first part is 616. pls i have a 34 on the assignment rn pls help
Marat540 [252]

Answer:

a) Ffloor = 616.56[N]

b) Ffloor = 484.16 [N]

Explanation:

In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.

Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.

ΣF = m*a

where:

F = force [N] (units of Newtons]

m = mass [kg]

a = acceleration [m/s²]

g = gravity acceleration = 9,81 [m/s²]

a)

F_{floor} -m*g = m*a

F_{floor} -(56*9.81)=56*1.2\\F_{floor}= 616.56[N]

b) Using Newton's second law we have.

F_{floor}-m*g= -m*a\\F_{floor}=-m*a+m*g\\F_{floor} = -(56*1.2) + (56*9.81)\\F_{floor} = 484.16 [N]

5 0
3 years ago
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