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Wewaii [24]
2 years ago
13

Which of the following describes the end behavior of the

Mathematics
1 answer:
slava [35]2 years ago
6 0
B . Approaches -4
I’m pretty sure it’s -4
You might be interested in
Can someone please help​
jeka57 [31]
16/5is the answer I hope it helpssssdnfjdksps
7 0
2 years ago
Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and
grigory [225]

Answer:

The correct option is:

Building B; it is around 16.35 feet taller than building A.

Step-by-step explanation:

Consult the diagram below where the first figure represent building A and second figure represents building B

For building A:

tan θ = Perpendicular / Base

tan 73° = Height of building A / 30

Height of building A = tan73 · 30

Height of building A = 98.13 ft

For building B:

tan θ = Perpendicular / Base

tan 73° = Height of building B / 35

Height of building A = tan73 · 35

Height of building A = 114.48 ft

Building B is taller

Difference in height = height of building B - height of building A

Difference in height = 114.48 - 98.13 = 116.35 feet

3 0
3 years ago
What percentage of 3 is 4?
Artyom0805 [142]

Answer:

13.333% of 3 is 4.

Step-by-step explanation:

Take missing value = x

x% of 3 = 4

x/100 × 3 = 4

3x/100 = 4

3x = 400

x = 400/3

x = 13.333

Hope it helps ⚜

5 0
2 years ago
Read 2 more answers
Based on the image and stated scale, what is the value of y?
GenaCL600 [577]

Answer:

2.2 inches

Step-by-step explanation:

This is because of the stated scale rate. 1/5 is equal to 20% with that 20% of 11 inches would yield 2.2 inches hope this helps :)

5 0
3 years ago
2. The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability th
coldgirl [10]

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

8 0
3 years ago
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