All categories

2 years ago

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Mathematics

2 answers:

Zina [86]2 years ago

7 0

Hello,

$12x^3-2x^2+15x-3\\
=2x^2(6x-1)+3(6x-1)\\
=(6x-1)(2x^2+3)
$

vazorg [7]2 years ago

7 0

Answer:

The answer is A. 2x2(6x – 1) + 3(6x – 1)

Step-by-step explanation:

You might be interested in

The Orchard Cafe has found that about 3% of the diners who make reservations don't show up. If 83 reservations have been made, h

daser333 [38]

Answer:

$\mu = 80.51\\\sigma = 1.56$

Step-by-step explanation:

We are given the following information in the question:

Percentage of of the diners who make reservations don't show up = 3%

Number of reservations = 83

Thus, we are given a binomial distribution with n = 83 and p = 0.97

$X\sim \text{ Binom}(p = 0.97, n = 83)$

$\mu = np = (83)(0.97) = 80.51$

Around 81 people can be expected to show up.

$\sigma = \sqrt{np(1-p)} = \sqrt{(83)(0.97)(1-0.97)} = 1.5541 \approx 1.56$

The standard deviation of this distribution is 1.56

6 0

2 years ago

1) Which variable did you plot on the x-axis, and which variable did you plot on the y-axis?

Liula [17]

Answer:

Step-by-step explanation:

This question is too difficult

3 0

2 years ago

36 2/5 x what = 109 1/5

tamaranim1 [39]

I am not sure what the answer is but covert them into a decimal and then divide it

6 0

3 years ago

Read 2 more answers

Find the greatest common factor of 24xz^2 and 8yz?

julia-pushkina [17]

Answer:

Step-by-step explanation:

8z (3x^2 +y)

5 0

2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

3 0

2 years ago