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4 years ago

Which of these is a source of voltage?

2 answers:

5 0

D, all of these are voltage sources. A battery can power small things, generators can power larger things, and outlets can charge, or power things.

Nostrana [21]4 years ago

3 0

The answer is all the Above.

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3. A car moves from rest with uniform acceleration along a horizontal road. After travelling a distance of 100 metres, it has ki

mrs_skeptik [129]

Explanation:

Given Data :

▪ Initial velocity = zero ( body is at rest)

▪ Distance travelled = 100m

▪ Final kinetic energy = 200000J

To Find :

▪ Resultant force acting on the car.

Therefore:

W = F × d = ΔK ----------------- eq 1.

where,

W = work done

F = applied force

d = distance

ΔK = change in kinetic energy

Calculation :

→ F × d = Kf - Ki ----------------- eq 2.

Where:

Kf = Final kinetic energy = 200000

Ki = initial kinetic energy = 0

Substituting our values into the formula from equation (2)

→ F × 100 = 200000 - 0

→ F = 200000/100

→ F = 2000N

8 0

3 years ago

An automobile has a mass of 1200 kg. what is its kinetic energy, in kj, relative to the road when traveling at a velocity of 50

snow_lady [41]

One thing you should notice. It is kind of weird. Ke has no direction so that fact that it has velocities associated with it does not matter. It becomes a scaler (something measured by amount alone).

General Formula
Ke = 1/2 m v^2
Formula for this problem
Ke = 1/2 m (v2)^2 - 1/2 m (v1)^2

Givens
m = 1200 kg
v2 = 100 km/hr = 100 km/h * [1 hour / 3600 sec] * [1000 m/ 1km] = 27.8 m/s
v1 = 50 km / hr = 13.9 m/s

Substitution and work.
================
delta Ke = 1/2 1200 (27.8)^2 - 1/2 1200 (13.9)^2
delta Ke = 463704 - 115926
delta Ke = 34778 Joules
delta Ke = 34.8 kJ

The change is 34.8 kJ which means that the vehicle gains 34.8 kJ

5 0

3 years ago

Whenever two apollo astronauts were on the surface of the moon, a third astronaut orbited the moon. assume the orbit to be circu

almond37 [142]

Missing question:
"Determine (a) the astronaut’s orbital speed v and (b) the period of the orbit"

Solution

part a) The center of the orbit of the third astronaut is located at the center of the moon. This means that the radius of the orbit is the sum of the Moon's radius r0 and the altitude ( $h=430 km=4.3 \cdot 10^5 m$ ) of the orbit:
$r= r_0 + h=1.7 \cdot 10^6 m + 4.3 \cdot 10^5 m=2.13 \cdot 10^6 m$
This is a circular motion, where the centripetal acceleration is equal to the gravitational acceleration g at this altitude. The problem says that at this altitude, $g=1.08 m/s^2$ . So we can write
$g=a_c= \frac{v^2}{r}$
where $a_c$ is the centripetal acceleration and v is the speed of the astronaut. Re-arranging it we can find v:
$v= \sqrt{g r}= \sqrt{(1.08 m/s^2)(2.13 \cdot 10^6 m)}=1517 m/s = 1.52 km/s$

part b) The orbit has a circumference of $2 \pi r$ , and the astronaut is covering it at a speed equal to v. Therefore, the period of the orbit is
$T= \frac{2 \pi r}{v} = \frac{2\pi (2.13 \cdot 10^6 m)}{1517 m/s} =8818 s = 2.45 h$
So, the period of the orbit is 2.45 hours.

6 0

3 years ago

Anyone please helps me with this question... I'm stuck..

Zolol [24]

Highest fluid potential energy: answer A
Because the fluid is pushed upwards and potential energy is function of height. Since point A is the highest, there is the highest potential energy.

highest fluid pressure: answer C
This is because it is at the bottom where you have a hydrostatic pressure component

increasing fluid speed: answer B
This is because the section of the pipe is smaller and in order to have the same fluid flow rate the speed must increase

7 0

3 years ago

What is the total displacement of the car after 5 h? Question 4 options: 0 km 15 km 20 km 40km.

Likurg_2 [28]

Displacement can be defined as the overall change in the position of the object. The displacement of the car in 5 hrs is 0 km.

Displacement:

It is a vector quantity that is defined as the overall change in the position of the object.

The formula for displacement is:

$s = s_f-s_i$