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Liula [17]
3 years ago
5

A rightward force of 460 N is applied to a 286-kg crate to accelerate it across the floor

Physics
1 answer:
Bess [88]3 years ago
4 0

Answer:

Acceleration = 1.61 m/s²

Explanation:

Given the following data:

Force = 460N

Mass = 286kg

To find the acceleration;

Force = mass * acceleration

Substituting into the equation, we have;

460 = 286 * acceleration

Acceleration = 460/286

Acceleration = 1.61 m/s²

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If current is passed through two parallel conductors in the same direction and the conductors are placed near each other, they will​ attract each other.

<h3>What is electric current?</h3>

Electric current can be defined as the flow of electrons.

Since electrons are easily removed from atom and are very mobile, the flow of electrons constitute an electric current.

Materials which allow electric current to flow through them are known as conductors. Examples of conductors are metals, and electrolytes.

On the other hand, materials which do not allow electric current to pass through them are known as insulators. Examples of insulators are wood and rubber.

The flow of current is known as electricity.

Parallel conductors with current flowing through them in the same direction are attracted to each other as a result of a magnetic field produced by the flow of current.

In conclusion, conductors allow electric current to pass through and the flow of current through a conductor produces a magnetic field.

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What is the speed of terminal velocity?
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A few examples:
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Zanzabum

Answer:

The maximum speed that the truck can have and still be stopped by the 100m road is the speed that it can go and be stopped at exactly 100m. Since there is no friction, this problem is similar to a projectile problem. You can think of the problem as being a ball tossed into the air except here you know the highest point and you are looking for the initial velocity needed to reach that point. Also, in this problem, because there is an incline, the value of the acceleration due to gravity is not simply g; it is the component of gravity acting parallel to the incline. Since we are working parallel to the plane, also keep in mind that the highest point is given in the problem as 100m. Solving for the initial velocity needed to have the truck stop after 100m, you should find that the maximum velocity the truck can have and be stopped by the road is 18.5 m/s.

Explanation:

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