Answer:
Option: c is correct.
Step-by-step explanation:
We are given that paco needs at least 3/8 yard of twine to build a model ship.
that is we require twine of amount greater than 3/8 yards.
<em>now we need to check among the given options which quantity is greater than 3/8 yards.</em>
a)
3/10 yard.
As we know that for two rational numbers with the same numerator but with different denominator the number whose denominator is smaller is a greater quantity.
Hence 3/10 < 3/8
Hence option a is incorrect.
b)
1/4 yard
As to compare to rational numbers we have to either make the numerator equal or their denominator equal. Hence here we multiply and divide 1/4 by 2 to get 8 in the denominator.
as 2/8 < 3/8
since the denominator is same and the number with the same denominator but with different numerator are compared as whose numerator is greater is a greater quantity.
Hence option b is incorrect.
c)
3/4 yard
Clearly both the numbers have the same numerator but different denominator and we know that for two rational numbers with the same numerator but with different denominator the number whose denominator is smaller is a greater quantity.
Hence 3/8 < 3/4
Hence, option c is correct.
d)
1/8 yard
clearly both the numbers have the same denominator and we know that for two rational numbers withe same denominator but with different numerator the number whose numerator is smaller is a smaller quantity.
Hence, 1/8 < 3/8
Hence, option d is incorrect.
7g - 6 = -20
Add 6 to both sides
7g = -14
Divide both sides by 7
g = -2
answer: g = -2
Answer:
Step-by-step explanation:
Volume of tank is 3000L.
Mass of salt is 15kg
Input rate of water is 30L/min
dV/dt=30L/min
Let y(t) be the amount of salt at any time
Then,
dy/dt = input rate - output rate.
The input rate is zero since only water is added and not salt solution
Now, output rate.
Concentrate on of the salt in the tank at any time (t) is given as
Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000
dy/dt= dV/dt × dM/dV
dy/dt=30×y/3000
dy/dt=y/100
Applying variable separation to solve the ODE
1/y dy=0.01dt
Integrate both side
∫ 1/y dy = ∫ 0.01dt
In(y)= 0.01t + A, .A is constant
Take exponential of both side
y=exp(0.01t+A)
y=exp(0.01t)exp(A)
exp(A) is another constant let say C
y(t)=Cexp(0.01t)
The initial condition given
At t=0 y=15kg
15=Cexp(0)
Therefore, C=15
Then, the solution becomes
y(t) = 15exp(0.01t)
At any time that is the mass.
The small number is 2.
The large number is 3.
<u>Step-by-step explanation:</u>
Let the two consecutive numbers be x and x+1.
- x be the small integer.
- x+1 be the large integer.
The sum of these two consecutive integers = small integer + large integer
The sum of these two consecutive integers is x+x+1 = (2x+1)
It is given that,
- The sum of two consecutive integers is one less than three times the smaller integer.
- This means that, (2x+1) is one less than three times the smaller integer.
- Here, the small integer is represented as x.
<u>Therefore, it can determined that :</u>
(2x+1) = 3x-1
Keeping x term on one side and constants on other side,
3x-2x = 1+1
x = 2
Therefore, the small number is 2 and the large number is x+1 = 3.
Answer:
1/3
Step-by-step explanation:
You add the marbles up and you get 24, now divide by 8 and you get 3. Which is equal to a 1/3 chance of getting the green marble.
