Answer:
There will be 143,67g CO2 produced
Explanation:
2 C6H6 + 15 O2 → 12 CO2 + 6 H2O
(42,5 g C6H6) / (78.1124 g C6H6/mol) = 0.54408775 mole C6H6
(113.1 g O2) / (31.9989 g O2/mol) = 3.534496 moles O2
0.54408775 mole of C6H6 would react completely with 0.54408775 x (15/2) = 4.080658 mole O2, but there is more O2 present than that, so O2 is in excess and C6H6 is the limiting reactant.
(0.54408775 mol C6H6) x (12/2) x (44.0096 g/mol) = 143.67 g CO2
Answer:- 0.456 L
Solution:- Looking at the given information, only volume and pressure are changing and the temperature is constant. We know that, at constant temperature, the volume of the gas is inversely proportional to the pressure.
= 735 torr
= 807 torr
= 500. mL
= ?
Let's plug in the values in the equation and solve it for final volume.
since, 1 L = 1000 mL
= 0.456 L
So, the volume of carbon dioxide at the new pressure will be 456 mL or 0.456 L.
- log (1.5 x 10^-3) = pOH = 2.824
<span>14 - 2.824 = pH = 11.176 </span>
<span>10 ^ (-11.176) = [H3O+] = 6.668 x 10^-12</span>
Salt and Water is the correct answer.
hope this helps!