Renewable resource:wind
Nonrenewable resource: natural gas
Use the universal gas formula
PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = 0.08205 L atm / (mol·K)
Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)
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Answer:
Option A = 14.19 atm
Explanation:
Given data:
Volume of gas = 2.50 L
Number of moles of gas = 1.35 mol
Temperature of gas = 320 K
Pressure of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will put the values in formula.
P × 2.50 L = 1.35 mol × 0.0821 atm.L/ mol.K× 320
P = 35.467 atm.L/ 2.50 L
P = 14.19 atm
Thus, option A is correct.
Answer:
Hydronium ion concentrations increase with decreasing pH values. So, the solutions with the lower pH values have the higher H₃O⁺ concentrations.
Explanation:
Answer:
V₂ = 1473.03 L
Explanation:
Given data:
Initial volume = 980 L
Initial pressure = 107.2 atm
Initial temperature = 71 °C (71 +273.15 = 344.15 K)
Final temperature = 13°C (13+273.15 = 286.15K)
Final volume = ?
Final pressure = 59.3 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 107.2 atm × 980L × 286.15 K / 344.15 K× 59.3 atm
V₂ = 30061774.4 atm .L. K / 20408.095 atm. K
V₂ = 1473.03 L
