Answer: The probability of selecting at least one boy (the probability that the 2 students selected are not both girls) is 62/95 or 0.6526
Step-by-step explanation:
From the question, the students to be chosen must be selected from a group of eight boys and twelve girls. This means that the total number of students that these two students must be chosen from is:
8 + 12 = 20 students.
The next step would be to find the probability of selecting a boy:
= Total number of boys/Total number of students
= 8/20
We will also find the probability of selecting one girl from the group
= Total number of girls/Total number of students
= 12/20
To find the probability that the two selected students are not girls is the same as finding the probability of selecting at least one boy. To do this, we will first find the probability of choosing all girls and then subtract it from 1.
The probability of selecting or choosing 2 girls (without replacement)
(12/20) × (11/19)
= 132/380
= 33/95
Then, the probability of selecting at least one boy (the probability that the students chosen are not both girls)
= 1 - (33/95)
= (95/95) - (33/95)
= 62/95 or 0.6526
The answer is: 3
Explanation: there’s a number pattern going on, in the first example they subtract by 3 each time. In the second example they subtract by 2 each time. So for the last one you have to do 9-6 which is 3 and that’s the number pattern.
Hope I helped :)
With what do you need help with
If we are supposed to assume that QS=TV
4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4
sub back
4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV
then answer is C
