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Vikentia [17]
2 years ago
10

What is an equation of the line that passes through the points (2, -1) and (3,-4)?

Mathematics
2 answers:
Wewaii [24]2 years ago
8 0

Answer:

y=3x+5

Step-by-step explanation:

gradient =(y2-y1)÷(x2-x1)

(-4--3)÷(3-2)

=-3/1

y=mx+c

y+1/x-2=_3/1

y+1=-3x+6

y=3x+5

zavuch27 [327]2 years ago
4 0

\huge\underline\mathtt\colorbox{orange}{ y = -3 x + 5}

<h2>Step-by-step explanation:</h2>

Find the equation of the line in slope-intercept form with the properties:

point: p_1 = (2, -1)

point: p_2 = (3, -4)

The slope of the line through points (x_1, y_1) and (x_2, y_2) is m = (y_2 - y_1)/(x_2 - x_1):

m = (-4 - (-1))/(3 - 2) = -3

Substitute the slope m = -3 and point (x_1, y_1) = (2, -1) into the point-slope equation y - y_1 = m (x - x_1):

y - (-1) = -3 (x - 2)

Subtract 1 from both sides:

y = -1 - 3 (-2 + x)

Distribute: -3 (x - 2) = 6 - 3 x:

Answer:

<u> y = -3 x + 5</u>

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Solve for x: 3(x + 1)= -2(x - 1) + 6.
pickupchik [31]

Answer:

x=1

Step-by-step explanation:

3(x + 1)= -2(x - 1) + 6.

Distribute

3x+3 = -2x+2+6

Combine like terms

3x+3 = -2x+8

Add 2x to each side

3x+3+2x = 8

5x+3 = 8

Subtract 3 from each side

5x =5

Divide by 5

x =1

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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