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Wittaler [7]
2 years ago
6

What is the exact value of the trigonometric expression in simplest form?

Mathematics
1 answer:
Bingel [31]2 years ago
4 0

Step-by-step explanation:

-  \sqrt{3}  + 4(  \frac{ \sqrt{3} }{2} )

-  \sqrt{3}  + 2 \sqrt{3}  =  \sqrt{3}

sqr root of 3

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Could someone please help me with this question? 15 points.
polet [3.4K]
1a) f(x) = I x+2 I. This is a piece-wise graph ( V form)
      x = 0 →f(x) =2 (intercept y-axis)
      x = -2→f(x) = 0 (intercept x-axis)
      x = -3→f(x) = 1 (don't forget this is in absolute numbers)
      x = -4→f(x) = 2 (don't forget this is in absolute numbers)
Now you can graph the V graph

1b) Translation: x to shift (-3) units and y remains the same, then
      f(x-3) = I x - 3 + 2 I = I x-1 I
     the V graph will shift one unit to the right, keeping the same y. Proof:
     f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
8 0
3 years ago
If (a^x a ^y) - a^z = a^m then express m in terms of x, y and z.​
omeli [17]

Answer:

m = x+y-z

Step-by-step explanation:

Given the expression.

(a^x a ^y) ÷ a^z = a^m

We are to express m in terms of x, y and z.

Using the multiplicative law of indices, the expression becomes:

a^{x+y} ÷ a^z = a^m

Applying the division rule in indices

a^{x+y} ÷ a^z = a^{x+y-z}

The equation becomes

a^{x+y-z} = a^m

Cancel out the base and equate the powers as shown:

x+y-z = m

Hence the expression of m in terms of x, y and z is m = x+y-z

8 0
3 years ago
Can someone please help me
Lelu [443]
1 true
2 false
3 false
4 true
8 0
2 years ago
Read 2 more answers
Write an algebraic expression for each word phrase. 10 less than x
iogann1982 [59]

Answer:

10

Step-by-step explanation:

10=10\\less\:than =

= 10

8 0
2 years ago
Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.
Step2247 [10]

Answer:

Remember, the expansion of (x+y)^n is (x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k, where \binom{n}{k}=\frac{n!}{(n-k)!k!}.

Then,

(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k

Then, the coefficient of the term p^{6-k}q^k is \binom{6}{k}5^{6-k}2^k

a) since 6-k=2, then k=4. So the coefficient of p^2q^4 is

\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000

b) since 6-k=5, then k=1. So, the coefficient of p^5q is

\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500

c) since 6-k=3, then k=3. So, the coefficient of p^3q^3 is

\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000

6 0
2 years ago
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