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diamong [38]
2 years ago
9

In a cross aabbcc x aabbcc, what is the probability of producing the genotype aabbcc?.

Biology
1 answer:
Anni [7]2 years ago
3 0

Answer:

1/8

Explanation:

Traditional method of solving this problem can be by using the punnett square.

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3.6 In mice, the allele C for colored fur is dominant over the allele c for white fur, and the allele V for normal behavior is d
KengaRu [80]

Answer:

a)  Parents Genotype should be (CC,Vv) and (cc,VV).

b) The genotypes of the parents are (Cc,Vv) and (Cc,Vv).

c) The genotypes of the parents are (Cc,Vv) and (cc,vv).

Explanation:

<h2>                                      (<u>a)</u> </h2>

Mating has occured between a normal colored mice whose genotype is C_,V_  and normal white  mice with genotype cc,V_. The offsprings are as follows :

1) normal mice produced 29 colored

2) 10 colored, waltzing progeny.

Thus all offspring are normal. The genotype of the first parent should therefore be CC. Waltzing trait is produced. The V gene should therefore be heterozygous in both traits.

Hence The parent genotypes should be<u> (CC,Vv) and (cc,CV).</u>

<h2>                                      (b)</h2>

In this case the approximate ratio in which the descendants are produced is 9:3:3:1. Hence genotypes of the parents are <u>(Cc,Vv) and (Cc,Vv). </u>

<h2>                                      (<u>c)</u>  </h2>

In this case the approximate ratio in which the offsprings are produced is 1:1:1. The genotypes of the parents are <u>(Cc,Vv) and (cc,vv). </u>

3 0
3 years ago
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