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Shkiper50 [21]
4 years ago
7

1. A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its

Physics
2 answers:
Amanda [17]4 years ago
5 0

Answer:tryna get points don't mind me

Explanation:

Bas_tet [7]4 years ago
4 0

Answer:

6 m/s²

Explanation:

Average acceleration = change in velocity / change in time

a = Δv / Δt

a = (22 m/s − 4 m/s) / 3 s

a = 6 m/s²

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Calculate the energy transfers in joules by a 4kW by appliances left for 2 minutes
Marianna [84]

Answer: 480 kJ

Explanation: Energy = power · time

E = Pt = 4000 W · 120 s = 480 000 J

5 0
3 years ago
A rugby player passes the ball 7.00 m across the field, where it is caught at the same height as it left his hand. If the pass w
Sauron [17]
<span>This projectile has been thrown in an oblique movement, so it’s moving in x and in y at the same time. Vy varies due to gravity, and Vx is a constant as there is no gravity in the horizontal direction. In order to calculate Vx, you have to use the angle: Vx=V*cosa=12m/s*cos(14.2)= 11.6m/s So now you should use Vx the same way it is used in a uniform linear movement. d=v*t dx=vx*t t=dx/vx=7m/(11.6m/s)=0.603s</span>
4 0
3 years ago
Which are the components of a typical refracting telescope? hints?
Ivenika [448]
<span>covex object and concave eyepiece.</span>
4 0
3 years ago
I need help figuring out the science question!!
Aleonysh [2.5K]

Answer:

Explanation:

Speed is the distance covered over the time taken to do so.

s = d/t = 45 m / 3 s = 15 m/s

6 0
3 years ago
An green hoop with mass mh = 2.8 kg and radius rh = 0.13 m hangs from a string that goes over a blue solid disk pulley with mass
Otrada [13]
The only force on the system is the mass of the hoop F net = 2.8kg*9.81m/s^2 = 27.468 N The mass equal of the rolling sphere is found by: the sphere rotates around the contact point with the table. 
So by applying the theorem of parallel axes, the moment of inertia of the sphere is computed by:I = 2/5*mR^2 for rotation about the center of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. 
I = 7/5*mR^2 M = 7/5*m 
Therefore, linear acceleration is computed by:F/m = 27.468 / (2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2 
7 0
4 years ago
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