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3 years ago

1. A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its

Physics

2 answers:

Amanda [17]3 years ago

5 0

Answer:tryna get points don't mind me

Explanation:

Bas_tet [7]3 years ago

4 0

Answer:

6 m/s²

Explanation:

Average acceleration = change in velocity / change in time

a = Δv / Δt

a = (22 m/s − 4 m/s) / 3 s

a = 6 m/s²

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Orange juice with pulp floating around is an example of what type of mixture?

kolbaska11 [484]

Answer:

I hope this helps

Explanation:

homogeneous mixture

8 0

4 years ago

Read 2 more answers

What height will the object reach? 12 points. Will give brainliest.

umka21 [38]

Answer:

12.7 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 56.7 Km/hr

Maximum height (h) =..?

First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:

Initial velocity (m/s) = 56.7 x 1000/3600

Initial velocity (m/s) = 15.75 m/s

Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:

Initial velocity (u) = 15.75 m/s

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

v = u – gt (since the ball is going against gravity)

0 = 15.75 – 9.8 × t

Rearrange

9.8 × t = 15.75

Divide both side by 9.8

t = 15.75/9.8

t = 1.61 secs.

Finally, we shall determine the maximum height as follow

h = ½gt²

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 1.61 secs.

Height (h) =..?

h = ½gt²

h = ½ × 9.8 × 1.61²

h = 4.9 x 1.61²

h = 12.7 m

Therefore, the maximum height reached by the ball is 12.7 m

3 0

3 years ago

A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west

Minchanka [31]

The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:

ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)

or equivalently,

$\vec v_{D/W}+\vec v_{W/E}=\vec v_{D/E}$

(see the attached graphic)

We have

ducks (relative to wind) = 7.0 m/s in some direction θ relative to the positive horizontal direction, or

$\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)$

wind (relative to Earth) = 5.0 m/s due East, or

$\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)$

ducks (relative to earth) = some speed v due South, or

$\vec v_{D/E}=v(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)$

Then by setting components equal, we have

$\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta+5.0\dfrac{\rm m}{\rm s}=0$

$\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v$

We only care about the direction for this question, which we get from the first equation:

$\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta=-5.0\dfrac{\rm m}{\rm s}$

$\cos\theta=-\dfrac57$

$\theta=\cos^{-1}\left(-\dfrac57\right)\text{ OR }\theta=360^\circ-\cos^{-1}\left(-\dfrac57\right)$

or approximately 136º or 224º.

Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies both equations. We want

$\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v$

which means θ must be between 180º and 360º (since angles in this range have negative sine).

So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.

8 0

3 years ago

if the mass of the marble is 0.025kg, and you assume that on the first drop of your roller coaster (height=8cm) the marble is fa

Nookie1986 [14]

1. What is the force of the marble?

For an object near the surface of the earth, the gravitational force acting upon the object is given by:

F = mg

F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.

Given values:

m = 0.025kg, g = 9.8m/s²

Plug in the given values and solve for F:

F = 0.025×9.8

F = 0.25N

2. What is the marble's potential energy at the start of its fall?

The gravitational potential energy of an object near the earth's surface is given by:

PE = mgh

PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.

new given values:

h = 0.08m

Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:

PE = F×h

PE = 0.25×0.08

PE = 0.02J

4 0

3 years ago

I need help with the last question- it’s very simple

77julia77 [94]

You calculated the density correctly.

When you drop anything into a fluid . . .

-- If the object is MORE dense than the fluid, it sinks.

-- If the object is LESS dense than the fluid, it floats.

3 0

3 years ago