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2 years ago

What are the measurements of 1 and 2?

Mathematics

1 answer:

8090 [49]2 years ago

8 0

Answer:

8 tablespoons1/2 cup4 ounces10 tablespoons plus 2 teaspoons2/3 cup5.2 ounces12 tablespoons3/4 cup6 ounces16 tablespoons1 cup8 ounces

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the admission fee for a charity event is $7 for children and $10 for adults the event was attended by 700 people on the total am

9966 [12]

Answer:

there were 200 children and 500 adults at the show

Step-by-step explanation:

7x+10y=6400

x+y=700

x=700-y

7(700-y)+10y=6400

4900-7y+10y=6400

-7y+10y=1500

3y=1500

y=500

x=700-y

x=700-500

x=200

3 0

2 years ago

Read 2 more answers

Need answers asap plz with work included (20 points)

svetoff [14.1K]

I think it would be B i hope this helps

3 0

3 years ago

What is seven less than three times a number.

sukhopar [10]

Let’s use y as a replacement for a number. You would do 3y-7 since you multiply by three and take away seven.

3 0

2 years ago

Read 2 more answers

A line perpendicular to the line y=5x+6

Ratling [72]

Answer:

y= -10x +12

Step-by-step explanation:

3 0

2 years ago

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$

$P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231$

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0

3 years ago