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Zepler [3.9K]
2 years ago
14

Pete grabbed 18 mixed nuts, StartFraction 2 Over 9 EndFraction of which were almonds. Which equation shows how to determine the

number of almonds Pete grabbed?
18 divided by StartFraction 2 Over 9 EndFraction = 81
18 times StartFraction 2 Over 9 EndFraction = 4
StartFraction 2 Over 9 EndFraction divided by 18 = StartFraction 1 Over 81 EndFraction
StartFraction 9 Over 2 EndFraction divided by 18 = one-fourth
Mathematics
2 answers:
GenaCL600 [577]2 years ago
7 0

Answer:

IT'S B I CAN CONFIRM BC I JUST FINISHED THE TEST

Step-by-step explanation:

djverab [1.8K]2 years ago
6 0

Answer:

18 times StartFraction 2 Over 9 EndFraction = 4

Amount of almonds = 18 × [2/9]

Amount of almonds =  4 almonds

Step-by-step explanation:

Given:

Number of mixed nuts = 18

Probability of almonds = 2/9

Find:

Amount of almonds

Computation:

Amount of almonds = Number of mixed nuts × Probability of almonds

Amount of almonds = 18 × [2/9]

Amount of almonds = 36 / 4

Amount of almonds =  4 almonds

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kirza4 [7]

Answer:

8 (x -9)

Step-by-step explanation:

I don't know if you ment 9 instead of 9, but if you did that that would be the answer!

7 0
4 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



7 0
3 years ago
Read 2 more answers
Help me solve please! The math club has 57 members who are in sixth or seventh grades. There are twice as many sixth graders as
saul85 [17]
We know there is 57 members are in the math club and there is twice as many sixth grades than the seventh. To find out how many sixth graders are in the club, we do:

x = seventh graders
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57=3x
57 ÷ 3 = 3x ÷3
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A survey indicated that 3 out of 5 doctors use brand X aspirin. If 2000 doctors were surveyed, how many used brand X?
Blizzard [7]
2000(3/5)

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For which distributions is the median the best measure of center?
Marat540 [252]

Answer:

it will be the correct answer..

because

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