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blondinia [14]
3 years ago
5

(b) A private club grew by 7 members each week for 42 weeks. What was the total change in the

Mathematics
1 answer:
natulia [17]3 years ago
5 0

Answer:

294

Step-by-step explanation:

42×7=294

The total change was the capacity.

You might be interested in
In the inequality, what are all the possible values of x?
Marat540 [252]

Answer:

B) \displaystyle x ≤ 0

Step-by-step explanation:

2(x + 12) − 16 ≤ 8

\displaystyle \frac{2(x + 12)}{2} ≤ \frac{24}{2} \\ \\ x + 12 ≤ 12 \\ \\ x ≤ 0

I am joyous to assist you anytime.

7 0
3 years ago
-4/5 + (-1/3) ??????
Nikitich [7]
-17/15

Find a common denominator, and multiply the numerator by the same factor. Don't forget that adding a negative is really subtracting.
5 0
3 years ago
Can someone please help I pay £100
Flura [38]

Answer:

The new points to the triangle will be:
A(1,4)\\ B(1,1)\\ C(-1,1)

Step-by-step explanation:

Because the reflection point is at x=2, all x values will subtract their distances from x=2 to get their new values. The y values remain the same.

The starting values are:

A(3,4)\\ B(3,1)\\ C(5 ,1)

Point A is 1 unit away from x=2, so we'll subtract 1 from 2 to get the new x value: 2 - 1 = 1, so A(1,4).

 

Point B is also 1 unit away from x=2, so we'll subtract 1 from 2 to get the new x value: 2 - 1 = 1, so B(1,1).

Point C is 3 units away from x=2, so we'll subtract 3 from 2 to get the new x value: 2 - 3 = -1, so C(-1,1).

3 0
2 years ago
10. Determine the open interval(s) on which the function f(x) = 12x - x^3 is increasing.
Gre4nikov [31]

Answer:

\large\boxed{x\in(-2,\ 2)}

Step-by-step explanation:

f(x)=12x-x^3

Calculate the derivative of the function:

f'(x)=\left(12x-x^3\right)'=(12x)'-\left(x^3\right)'=12-3x^2

Calculate the zeros of the derivative:

f'(x)=0\Rightarrow12-3x^2=0\qquad\text{add}\ 3x^2\ \text{to both sides}\\\\3x^2=12\qquad\text{divide both sides by 3}\\\\x^2=4\to x=\pm\sqrt4\\\\x=\pm2

Let's check the derivative sign:

f'(x)>0\iff12-3x^2>0\qquad\text{use the distributive property}\\\\-3(x^2-4)>0\\\\-3(x^2-2^2)>0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\-3(x-2)(x+2)>0\\^{\qquad x=2\qquad x=-2

Sketch a parabola open down

(before the brackets there is the number -3 < 0)

Look at the picture.

Where the derivative is negative, the function decreases.

Where the derivative is positive, the function increases.

Therefore your answer is:

x\in(-2,\ 2)

3 0
3 years ago
Let log p/n=6 and log m/n=8 what is the relationship between p and m?
Mrac [35]
By the laws of logs
log p/n =  log p - log n  = 6
log m/n = log m - log n   = 8        subtract
 
 log m - log p =  2
 
log m/p = 2

So m / p = 100 
6 0
3 years ago
Read 2 more answers
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