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2 years ago

How is HL related to KHF? Explain.

Mathematics

1 answer:

ratelena [41]2 years ago

6 0

Answer: →

HL bisects ∠KHF because L is equidistant from HK and HF.

Step-by-step explanation: The converse of the angle bisector theorem says that if point on the interior of an angle is equidistant from the sides of the angle, then the point is on the angle bisector

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Find the value of X.

-Dominant- [34]

To find the value of x we first need to find the missing angle in the triangle.

To do that we are gonna add the angles we already have.

64 + 45 = 109

Angles in a triangle measures 180 so to get the missing angle we are gonna subtract 109 from 180

180 - 109 = 71 deg

The missing angle in the triangle is 71 deg

Angles on a straight line adds up to 10 so to find x we are gonna subtract 71 from 180

180 - 71 = 109 degrees

Therefore x is 109 degrees.

6 0

3 years ago

2 u + 12 < 23 0,1 d + 8 > 0 3 - 4 r > 7 13 < 2 z + 3 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

The question is

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

3 years ago

What is the median of this set of data? 1, 2, 5, 6,9

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

median = (n+1)/2 th item

n = 5

median = 3rd item = 5

3 0

3 years ago

Please help ASAP 25 pts + brainliest to right/best answer

Whitepunk [10]

The answer seems to be D!!

4 0

3 years ago

Read 2 more answers

A rectangle has a perimeter of 16p centimeters. It has a width of 2p centimeters. Find the length of the rectangle in terms of p

DIA [1.3K]

If the width is 2p then the width of both sides is 4p. Subtract that from the total perimeter and you get 16p-4p= 12p. Divide that by two because there are 2 side lengths. So, one side length is 6p.

6 0

2 years ago

Read 2 more answers