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3 years ago

……….help…..me …….pls..

Mathematics

1 answer:

svet-max [94.6K]3 years ago

5 0

Answer:

Here,

(cosθ + sinθ/sinθ) – (cosθ – sinθ/cosθ) = secθ cscθ

Now, Cross Multiplication

(cosθ + sinθ/sinθ) – (cosθ – sinθ/cosθ) = secθ cscθ

cosθ(cosθ + sinθ) – sinθ(cosθ – sinθ)/sinθ cosθ

cos²θ + sinθ cosθ – sinθ cosθ + sin²θ/sinθ cosθ

cos²θ + sin²θ/sinθ cosθ

Here, we know the identity

cos²θ + sin²θ = 1

So,

cos²θ + sin²θ/sinθ cosθ can be written as

1/sinθ cosθ

Here, we also know the identity

1/sinθ = cscθ

1/cosθ = secθ

1/sinθ cosθ can be written as

secθ cscθ

= L.H.S

Hence Proved!!

-TheUnknownScientist 72

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4 years ago

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