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mars1129 [50]
2 years ago
9

Expand the logarithm fully using the properties of logs. Express the final answer in

Mathematics
1 answer:
Arturiano [62]2 years ago
6 0

\begin{array}{llll} \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \end{array} ~\hfill \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\[-0.35em] ~\dotfill\\\\ \log\left( \cfrac{x^2}{y^4} \right)\implies \log(x^2)-\log(y^4)\implies 2\log(x)-4\log(y)

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Choose one of the factors of 27x^3 + 512y^3.
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4j + 4j − 6j − j = 12 <br> Solve for J
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Read 2 more answers
Solving by elimination <br> -6x+6y=6 -6x+3y=-12
labwork [276]
So elimination method is basically adding the equations and canceling out variables. 
-6x + 6y = 6
-6x + 3y = -12
The eaiest way to solve is by multiplying the bottom equation by -1.
-6x + 6y = 6
 6x - 3y = 12
Now you add the eqautions.
3y = 18
Divde 3 from both sides.
y = 6
Now plug in 6 into any of the original two equations. Lets use the first one.
-6x + 6(6) = 6
-6x + 36 = 6
Subtract 36 from both sides.
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Divide -6 from both sides.
x = 5
So your solution is (5, 6).
I hope this helps love! :)
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