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jeka57 [31]
3 years ago
7

This question is about the alpha particle experiment

Physics
1 answer:
Wewaii [24]3 years ago
4 0
This suggest the the atom has a very small positively charged nucleus in the mass of the atom is concentrated. 
And the electrons revolves around the nucleus in their orbits.
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Between which two planets is the gravitational attraction the weakest?
raketka [301]

planet B and D have the weakest gravitational attraction.

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3 years ago
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A helium atom consists of two protons, two
finlep [7]
In the helium atom, the strong force is a fundamental interaction between the "<span>(4) neutrons and protons" and it should be noted that this is the case for most atoms. </span>
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3 years ago
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The energy of an onject as it is in motion is defined as?
Ivan

The energy of an object as it is in motion is defined as Kinetic energy.

<u>Explanation:</u>

The energy that is attained by an object when it is moving is called as Kinetic energy. It is the amount of energy that is essential for inducing an acceleration in an object and making it to displace from its idle position to the destination. When an object attains the acceleration it can have this kinetic energy until there is a change in the speed of the object with which it moves.

The forms of energy changes and it can take any form like thermal, electrical, electromagnetic,etc. Potential and kinetic energy are the two things under which these forms are energy are grouped. There can be a transferring of Kinetic energy from one object to another. The kinetic energy can also take any form of energy.  

7 0
3 years ago
Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

where G is the gravitational constant

M is the Earth's mass

R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

The Earth's volume is (approximating the Earth to a perfect sphere)

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3

So, the average density of the Earth is

\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3

4 0
3 years ago
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Water is traveling through a horizontal pipe with a speed of 1.7 m/s and at a pressure of 205 kPa. This pipe is reduced to a new
Arturiano [62]

Answer:

The velocity is  v_2 =  6.8 \ m/s

The pressure is  P_2 =  204978 Pa

Explanation:

From the question we are told that

 The speed at which water is travelling through is  v = 1.7 \ m/s

  The pressure is  P_1 = 205  k  Pa =  205 *10^{3} \ Pa

   The diameter of the new pipe is d =  \frac{D}{2}

Where D is the diameter of first pipe

   

According to the principal of continuity we have that

       A_1 v_1 =  A_2 v_2    

Now  A_1 is the area of the first pipe which is mathematically represented as

       A_1 = \pi  \frac{D^2}{4}

and  A_2 is the area of the second pipe which is mathematically represented as  

       A_2 = \pi  \frac{d^2}{4}

Recall   d =  \frac{D}{2}

        A_2 = \pi  \frac{[ D^2]}{4 *4}

        A_2 = \frac{A_1}{4}

So    A_1 v_1 =  \frac{A_1}{4}  v_2

substituting value

        1.7 =  \frac{1}{4}  * v_2    

        v_2 =  4 * 1.7    

       v_2 =  6.8 \ m/s

   

According to Bernoulli's equation  we have that

     P_1 + \rho \frac{v_1 ^2}{2} =  P_2 + \rho \frac{v_2 ^2}{2}

substituting values

     205 *10^{3 }+ \frac{1.7 ^2}{2} =  P_2 +  \frac{6.8 ^2}{2}

     P_2 =  204978 Pa

4 0
3 years ago
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