Answer: 581 gmol
0.581 kmol
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
1. The conversion for mol to gmol
1 mol = 1 gmol
581 mol=
2. The conversion for mol to kmol
1 mol = 0.001 kmol
581 mol=
3. The conversion for mol to lbmol
1 mol =
581 mol=
Answer:
200 watts
Explanation:
First we have to find total work:
W =F(d)
W = 400J
Then plug that answer into the Power formula.
P = W/(t_f-t-i)
P = 400/2s
P = 200 W
Answer: P2 = 0.858 atm
Explanation:
Use the combined gas law: P1V1/T1 = P2V2/T2,
where the subscripts are the initial (1) and final (2) states. Temperature must be in Kelvin. We want P2, so rearrange the equation to solve for P2:
P2 = P1(V1/V2)(T2/T1)
Note how I've arranged the volume and temperature values: as ratios. Now it is easy to cancel units and see what is going to happen to the pressure if we lower the temperature. Since the pressure change is a function of (T2/T1), and we are lowering the temperature (T2), we'd expect this to decrease the pressure.
No information is given on volume, so we'll assume a convenient value of 1 liter. Now enter the data:
P2 = (0.917atm)*(1)*(322K/344K)
P2 = 0.858 atm
1) we find out the volume of the water.
Remember: 1 ml=1 cm³
Volume of the water=number of cups x volume of one cup.
Volume of the water=2.5(240 ml)=600 ml=600 cm³
Density=mass/volume ⇒ mass=density x volume
2) we calculate the water mass of 600 cm³ of water.
mass=density x volume
mass=(1 g/cm³)(600 cm³)=600 g.
Answer: the mass of 2.5 cupas of water is 600 g.
The reactions are a bit poorly written. While it's true that aqueous H₂CO₃ is produced in this neutralization reaction, the H₂CO₃ rapidly decomposes to yield CO₂(g) and H₂O(l). Writing the product as H₂CO₃(aq) in the net ionic equation is unnecessarily confusing since it portrays the substance as nonionizing yet water-soluble.
In any case, the Na⁺ and the Cl⁻ are the spectator ions here.