Answer:
It would take 5 days
Explanation:
1. 2.5 times 8 is 20 ounces
2. 2.5 times 16 is 40 ounces
3. 2.5 times 24 is 60 ounces
4. 2.5 times 32 is 80 ounces
5. 2.5 times 40 is 100 ounces
According to Newton's first law of motion, it takes an unbalanced force to move an object at rest.
I hope this helps :)
<h3>
Answer:</h3>
0.89 J/g°C
<h3>
Explanation:</h3>
Concept tested: Quantity of heat
We are given;
- Mass of the aluminium sample is 120 g
- Quantity of heat absorbed by aluminium sample is 9612 g
- Change in temperature, ΔT = 115°C - 25°C
= 90°C
We are required to calculate the specific heat capacity;
- We need to know that the quantity of heat absorbed is calculated by the product of mass, specific heat capacity and change in temperature.
That is;
Q = m × c × ΔT
- Therefore, rearranging the formula we can calculate the specific heat capacity of Aluminium.
Specific heat capacity, c = Q ÷ mΔT
= 9612 J ÷ (120 g × 90°C)
= 0.89 J/g°C
Therefore, the specific heat capacity of Aluminium is 0.89 J/g°C
Answer:
The elastic potential energy stored in the stretched rubber band changes to kinetic energy.
Explanation:
Joshua hooks a rubber band between his thumb and forefinger. He moves his fingers apart, stretching the rubber band---- Here potential Energy is stored which is an energy that the rubber band has because of its position and it's potential to be converted into kinetic energy.
With a quick, sudden motion, he bends his thumb forward so that the rubber band slips off----The elastic potential energy stored in the stretched rubber band will change to kinetic energy, which is the Energy in Motion and work needed to accelerate the rubber band from rest to its stated or new position.
Answer:
Option B. 4.25×10¯¹⁹ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 6.42×10¹⁴ Hz
Energy (E) =?
Energy and frequency are related by the following equation:
Energy (E) = Planck's constant (h) × frequency (f)
E = hf
With the above formula, we can obtain the energy of the photon as follow:
Frequency (f) = 6.42×10¹⁴ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 6.63×10¯³⁴ × 6.42×10¹⁴
E = 4.25×10¯¹⁹ J
Thus, the energy of the photon is 4.25×10¯¹⁹ J
