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xxTIMURxx [149]
2 years ago
7

A parabola opens down and its vertex is (2, 5). What is the range of this function?

Mathematics
1 answer:
Margaret [11]2 years ago
7 0

The range of the parabola that opens down and has its vertex as (2, 5) is (b) (-\infty,5]

<h3>Vertex</h3>

The vertex of a parabola can represent the minimum or the maximum point in the parabola

The vertex of the parabola is given as:

(h,k) = (2,5)

<h3>The range</h3>

The range of a function is the set of output values the function can take

From the question, we understand that the parabola opens down.

This means that, the vertex of the parabola is a maximum.

Hence, the range of the parabola is (-\infty,5]

Read more about parabola at:

brainly.com/question/13136492

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Answer:

c

Step-by-step explanation:

Because you can't have multiple x-values. You can only have multiple y-values.

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Using new equipment, a worker finished 4 more parts in an hour than was planned and fulfilled his daily task not in 8 hours, but
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iris [78.8K]

Answer:

<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>

Step-by-step explanation:

<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14

<em>2. Now let us break this expression into groups:  </em>

3y^2 - 6y + 7y - 14  ⇒ ( 3y^2 - 6y )( 7y - 14 )

<em>3. Factor 3y from 3y^2 - 6y:</em>

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<em>4. Factor 7 from 7y - 14:</em>

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<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>

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<em>6. Factor common term y - 2:</em>

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