How are prisms and raindrops alike?

Please help help ASAP Please help It’s do in a 1 hour What conclusion can you draw about the relationship between physical activ

hjlf

Answer:

During exercise, heart rate can rise dramatically, from a resting rate of 60–80 beats per minute to a maximum rate of about 200 for a young adult. While you are running, blood flow is diverted toward tissues that need it most. For example, muscles in the arteries in your legs relax to allow more blood flow.

Explanation:

3 0

3 years ago

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The pressure caused by a sample of gas is 2.25 atm. 1 atm is

nexus9112 [7]

Answer:

$0.326\frac{N}{cm^2}$

Explanation:

Hello.

In this case, considering that 1 atm equals 1.01 kPa, we can compute the pressure in kPa first as shown below:

$2.25atm*\frac{1.01kPa}{1atm} =3.26kPa$

Now, we convert kPa to Pa, considering 1 kPa equals 1000 Pa:

$3.26kPa*\frac{1000Pa}{1kPa}=3260Pa$

Now, since Pa is equal to N/m², and 1 m equals 100 cm, the pressure in newton per square centimeter turns out:

$3260\frac{N}{m^2}*(\frac{1m}{100cm})^2 \\\\0.326\frac{N}{cm^2}$

Best regards.

4 0

3 years ago

7-¿Cuántos moles de CO2 estarán encerrados en un recipiente metálico a una presión de 1.10 Atm. y una temperatura de 31 °C, sabi

Aleks [24]

Answer:

7- 0.69 moles.

8- El nuevo volumen es 3.8L.

Explanation:

7- Usando la ley general de los gases:

PV = nRT

PV / RT = n

<em>P es presión = 1.10atm</em>

<em>V es volumen = 15.70L</em>

<em>R es constante de los gases = 0.082atmL/molK</em>

<em>T es temperatura absoluta = 31°C + 273.15K = 304.15K</em>

<em />

Reemplazando:

1.10atm*15.70L / 0.082atmL/molK*304.15K = n

<h3>0.69 moles</h3><h3 />

8- La ley combinada de los gases establece como ecuación:

P1V1 / T1 = P2V2 / T2

<em>Donde P1 es la presión inicial = 760mmHg</em>

<em>V1 volumen inicial = 2L</em>

<em>T1 es temperatura absoluta = 273.15 + 27 = 300.15K</em>

<em />

Reemplazando:

760mmHg*2L / 300.15K = 380mmHg*V2 / 285.15K

3.8L = V2

<h3>El nuevo volumen es 3.8L</h3>

4 0

3 years ago

Name:_____________________________________________________ Date:___________ Period:_________ 3/23 - 3/27 Assignment 1: Gas Law P

crimeas [40]

Answer:

The answers are;

1. 8.2 liters

2. 1214.84 ml

3. 318.027 K

4. 4.00 l.

Explanation:

1. Boyle's law states that the volume of given mass of gas is inversely proportional to its pressure at constant temperature

that is

P₁·V₁ = P₂·V₂

Where:

P₁ = Initial pressure = 40.0 mm Hg

V₁ = Initial volume = 12.3 liters

P₂ = Final pressure = 60.0 mm Hg

V₂ = Final volume = Required

From P₁·V₁ = P₂·V₂, V₂ is given by

$V_2=\frac{P_1\cdot V_1}{P_2} = \frac{40.0 mm Hg\cdot 12.3 l}{60.0 mm Hg}$ = 8.2 l

The volume reduces to V₂ = 8.2 liters

2. Here Charles law states that

$\frac{T_1}{V_1} =\frac{T_2}{V_2}$

T₁ = Initial temperature = 27.0 °C = 300.15 K

V₁ = Initial volume = 900.0 mL

T₂ = Final temperature = 132.0 °C = 405.15 K

V₂ = Final volume = Required

Therefore $V_2 =\frac{T_2\cdot V_1}{T_1}$ = $\frac{405.15 K\times 900.0 mL}{300.15 K}$ = 1214.84 ml

V₂ = 1214.84 ml

3. Gay-Lussac's Law states that

$\frac{T_1}{P_1} =\frac{T_2}{P_2}$

Where:

P₁ = Initial pressure = 15.0 atmospheres

T₁ = Initial temperature = 25.0 °C = 298.15 K

P₂ = Final pressure = 16.0 atmospheres

T₂ = Final temperature = Required

∴ $T_2 = \frac{T_1\times P_2}{P_1}$

= $\frac{298.15 K\times 16.0atm}{15.0atm}$ = 318.027 K

T₂ = 318.027 K

4. Avogadro's law states that,

Equal volume of all gases at the same temperature and pressure contain equal number of molecules.

Therefore if 5.00 moles of gas occupies 2.00 l volume, then

1 moles will occupy 2.00/5 l volume and

10 moles will occupy 2.00/5 × 10 or 4.00 l volume.

6 0

3 years ago

Think of a situation where "particle motion" is a blessing in disguise for the entire humanity.

valkas [14]

The concept of particle motion, not just a "blessing in disguise" but a significant concept in which humanity must learn about. The theory of particle motion simply states that "the particles which comprise matter, are constantly moving." For example in the application of aerosol sprays, particle motion is important because the aerosol particles would constantly disperse instead of being in a single position.

8 0

3 years ago